If a + b + c = 8 and ab + bc + ca = 11, then what is the value of a 3+ b 3+ c 3- 3abc?
248
The correct answer is 248.
Substitute all values into the main identity: (8)(42 - 11) . Perform the calculation: 8 \times 31 = 248 . Result The value of a^3 + b^3 + c^3 - 3abc is 248. These identities help in solving various problems involving polynomials and algebraic expressions efficiently.
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