We are given the following information:
We need to find the value of $a^2 + b^2 + c^2$.
We use the algebraic identity:
$ (a + b + c)^2 = a^2 + b^2 + c^2 + 2(ab + bc + ca) $
Substitute the known values into the identity:
$ (10)^2 = a^2 + b^2 + c^2 + 2(31) $
Simplify the equation:
$ 100 = a^2 + b^2 + c^2 + 62 $
Isolate $a^2 + b^2 + c^2$:
$ a^2 + b^2 + c^2 = 100 - 62 $
$ a^2 + b^2 + c^2 = 38 $
The value of $a^2 + b^2 + c^2$ is 38.
If $a + b + c = 0$, then find the value of $\frac{(a^2+b^2+c^2)^2}{a^2b^2+b^2c^2+c^2a^2}$
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