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Question

Given below are two statements:
Statement-I : $[Fe(ox)_3]^{3-}$ is chiral.
Statement-II : $trans-[Cr(H_2O)_2(ox)_2]^-$ is chiral.
(Given : $oxH_2 = HOOC-COOH$)
In light of the above statements, choose the most appropriate answer from the options given below:

This question was previously asked in
NEET UG Re-Exam 2026 Question Paper (21-Jun-2026)
The correct answer is
Statement-I is correct but Statement-II is incorrect.

Analysis of Statement I: $[Fe(ox)_3]^{3-}$ is chiral.

  • The complex $[Fe(ox)_3]^{3-}$ involves a central $Fe^{3+}$ ion coordinated to three oxalate ($ox^{2-}$) ligands.
  • The oxalate ligand ($ox^{2-}$) is a bidentate ligand, meaning it binds to the metal ion through two donor atoms.
  • The complex has the coordination number 6 and adopts an octahedral geometry.
  • Complexes of the type $[M(AA)_3]$, where AA is a bidentate ligand like oxalate, are generally chiral. This is because the arrangement of the three bidentate ligands around the central metal atom results in non-superimposable mirror images.
  • Specifically, $[Fe(ox)_3]^{3-}$ exists as a pair of enantiomers (dextro and levo rotatory forms).
  • Therefore, Statement-I is correct.

Analysis of Statement II: $trans-[Cr(H_2O)_2(ox)_2]^-$ is chiral.

  • The complex is $trans-[Cr(H_2O)_2(ox)_2]^-$. It contains a central $Cr^{3+}$ ion, two monodentate water ($H_2O$) ligands, and two bidentate oxalate ($ox^{2-}$) ligands.
  • The 'trans' designation indicates that the two $H_2O$ ligands are positioned opposite to each other (180° apart) in the octahedral geometry.
  • When the two $H_2O$ ligands occupy trans positions, the two oxalate ligands must coordinate in the remaining four equatorial positions. Each oxalate ligand chelates two adjacent coordination sites.
  • In this specific trans configuration, the complex possesses planes of symmetry. One plane can pass through the $Cr$ ion and the two $H_2O$ ligands. Another plane can pass through the $Cr$ ion and contain the four atoms coordinated by the two oxalate ligands.
  • The presence of a plane of symmetry makes the molecule achiral.
  • Therefore, Statement-II is incorrect.

Conclusion on Statements

Based on the analysis:

  • Statement-I is correct.
  • Statement-II is incorrect.

This matches the option stating that Statement-I is correct and Statement-II is incorrect.

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Important Questions from Inorganic Chemistry

  1. A chromium complex with a formula $\text{CrCl}_3\cdot 6\text{H}_2\text{O}$ has a spin only magnetic moment value of $3.87 \text{ BM}$ and its solution conductivity corresponds to $1 : 2$ electrolyte. $2.75 \text{ g}$ of the complex solution was initially passed through a cation exchanger. The solution obtained after the process was reacted with excess of $\text{AgNO}_3$. The amount of $\text{AgCl}$ formed in the above process is _____ g. (Nearest integer)
    [Given: Molar mass in $\text{g mol}^{-1}$ $\text{Cr} : 52; \text{Cl}: 35.5, \text{Ag}: 108, \text{O}: 16, \text{H}: 1$]
  2. Consider the following reactions :
    $\text{NaCl} + \text{K}_2\text{Cr}_2\text{O}_7 + \text{H}_2\text{SO}_4 \rightarrow \text{A} + \text{KHSO}_4 + \text{NaHSO}_4 + \text{H}_2\text{O}$
    $\text{A} + \text{NaOH} \rightarrow \text{B} + \text{NaCl} + \text{H}_2\text{O}$
    $\text{B} + \text{H}_2\text{SO}_4 + \text{H}_2\text{O}_2 \rightarrow \text{C} + \text{Na}_2\text{SO}_4 + \text{H}_2\text{O}$
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