This problem asks us to calculate the number of photons emitted per second by a bulb, given its power rating, light conversion efficiency, and the energy of a single photon.

Calculating Light Power Output

First, we determine the actual power converted into light. The bulb is rated at 150 watt, which means it consumes 150 Joules of energy per second ($150 \text{ J/s}$). However, only 8% of this energy is converted into light.

Power converted to light ($P_{light}$) is calculated as:

$ P_{light} = P_{total} \times \text{efficiency} $

Where:

• $P_{total} = 150 \text{ W} = 150 \text{ J/s}$
• Efficiency $= 8\% = 0.08$

Substituting the values:

$ P_{light} = 150 \text{ J/s} \times 0.08 = 12 \text{ J/s} $

So, the bulb emits 12 Joules of light energy every second.

Determining Photons Per Second

Next, we use the energy of a single photon to find out how many photons make up this light energy emitted each second.

The energy of one photon ($E_{photon}$) is given as $4.42 \times 10^{-19} \text{ J}$.

The number of photons emitted per second ($N$) can be found by dividing the total light power ($P_{light}$) by the energy per photon ($E_{photon}$):

$ N = \frac{P_{light}}{E_{photon}} $

Substitute the known values:

$ N = \frac{12 \text{ J/s}}{4.42 \times 10^{-19} \text{ J/photon}} $

Now, perform the calculation:

$ N = \frac{12}{4.42} \times 10^{19} \text{ photons/s} $

$ N \approx 2.7149 \times 10^{19} \text{ photons/s} $

Rounding to two decimal places, we get approximately $2.71 \times 10^{19}$ photons per second.