In octahedral complexes, the d-orbitals split into a lower energy set ($t_{2g}$) and a higher energy set ($e_g$). The number of unpaired electrons depends on the total number of d-electrons (the $\text{d}^{n}$ configuration) and the spin state, determined by ligand field strength.
We calculate the unpaired electrons for each specified configuration:
To find the total number of unpaired electrons, we sum the values calculated for each system:
Total = (Unpaired $\text{d}^{3}$) + (Unpaired $\text{d}^{4}$ low spin) + (Unpaired $\text{d}^{5}$ high spin) + (Unpaired $\text{d}^{6}$ high spin) + (Unpaired $\text{d}^{7}$ low spin)
Total = $3 + 2 + 5 + 4 + 1 = 15$.
Thus, the total number of unpaired electrons is 15.
The crystal field splitting energy of $[\text{Co(oxalate)}_3]^{3-}$ complex is '$n$' times that of the $[\text{Cr(oxalate)}_3]^{3-}$ complex. Here '$n$' is ___________. (Assume $\Delta_o >> P$)
The correct order of spin-only magnetic moments among the following is :
(Atomic number : Mn = 25, Co = 27, Ni= 28, Zn = 30)
The crystal field splitting energy of $[\text{Co(oxalate)}_3]^{3-}$ complex is '$n$' times that of the $[\text{Cr(oxalate)}_3]^{3-}$ complex. Here '$n$' is ___________. (Assume $\Delta_o >> P$)