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Question

For a histogram based on a frequency distribution with unequal class intervals, the frequency of a class should be proportional to:

The correct answer is

the area of the rectangle.

Understanding Histograms and Frequency Representation

A histogram is a graphical representation of the distribution of numerical data. It is an estimate of the probability distribution of a continuous variable. It is similar to a bar chart, but it groups numbers into ranges (bins or class intervals), and the bars represent the frequency or relative frequency of data points in each range.

In a standard histogram where all the class intervals have the same width, the height of each rectangular bar is directly proportional to the frequency of observations within that class interval. This makes it easy to compare the frequencies visually by looking at the heights of the bars.

Histograms with Unequal Class Intervals

However, when the class intervals have unequal widths, simply making the height proportional to the frequency would be misleading. A wide interval with a relatively low frequency might appear visually more significant than a narrow interval with a higher frequency if height alone represents frequency. To accurately represent the frequency distribution while accounting for varying class widths, we need to use the area of the rectangle to be proportional to the frequency.

To achieve this, the height of the rectangle for a class with unequal width is adjusted. We use a concept called Frequency Density.

Frequency Density is calculated as:

\( \text{Frequency Density} = \frac{\text{Frequency}}{\text{Class Width}} \)

When constructing a histogram with unequal class intervals, the height of the rectangle for each class is made proportional to its frequency density. The base of the rectangle is the class width.

Let's look at how the area relates to the frequency using this approach:

  • Height of the rectangle is proportional to Frequency Density.
  • Height \( \propto \frac{\text{Frequency}}{\text{Class Width}} \)
  • To make the area proportional to frequency, we set the height such that:
  • Height \( = k \times \frac{\text{Frequency}}{\text{Class Width}} \), where \(k\) is a constant of proportionality (often taken as 1).

The area of the rectangle is given by:

\( \text{Area} = \text{Height} \times \text{Class Width} \)

Substituting the height based on frequency density:

\( \text{Area} = \left( k \times \frac{\text{Frequency}}{\text{Class Width}} \right) \times \text{Class Width} \)

\( \text{Area} = k \times \text{Frequency} \)

This shows that the area of the rectangle is directly proportional to the frequency of the class, regardless of the class width. This is the correct way to represent frequency in histograms with unequal class intervals, as it ensures the visual impact of each bar accurately reflects the total frequency within that interval.

Analyzing the Options for Histograms

Let's consider the given options in the context of a histogram with unequal class intervals:

  1. The height of the rectangle: As discussed, if class intervals are unequal, making the height proportional to frequency would be misleading. The height is proportional to frequency density, not frequency itself. So, this option is incorrect.
  2. The area of the rectangle: By using frequency density for height, the area of the rectangle (height × width) becomes proportional to the frequency. This correctly represents the frequency for unequal class intervals. So, this option is correct.
  3. The width of the rectangle: The width of the rectangle represents the class interval width. While related to the calculation (used in frequency density), the frequency is not directly proportional to the width itself. So, this option is incorrect.
  4. The perimeter of the rectangle: The perimeter depends on both height and width. Since frequency is proportional to area (height × width), it is not directly proportional to the perimeter (2 × (height + width)). So, this option is incorrect.

Therefore, for a histogram based on a frequency distribution with unequal class intervals, the frequency of a class should be proportional to the area of the rectangle.

Comparison: Equal vs. Unequal Class Intervals
Feature Equal Class Intervals Unequal Class Intervals
Representing Frequency Height of the rectangle Area of the rectangle
Bar Height Represents Frequency Frequency Density
Visual Comparison Easily comparing heights Comparing areas (visually less intuitive, but mathematically correct)

Revision Table: Key Concepts in Histograms

Histogram Key Concepts
Term Definition/Formula
Histogram A bar graph showing frequency distribution of continuous data.
Class Interval A range of values for grouping data in a histogram.
Frequency The number of data points in a class interval.
Class Width The difference between the upper and lower limits of a class interval.
Frequency Density \(\frac{\text{Frequency}}{\text{Class Width}}\). Used for height when intervals are unequal.
Height (Equal Intervals) Proportional to Frequency.
Height (Unequal Intervals) Proportional to Frequency Density.
Area (Any Histogram) Proportional to Frequency. (Height x Width)

Additional Information on Frequency Distribution Graphs

Histograms are just one way to visualize frequency distributions. Other related graphs include:

  • Frequency Polygon: Created by joining the midpoints of the tops of the bars in a histogram with line segments.
  • Ogives (Cumulative Frequency Graphs): Plots the cumulative frequency against the upper class boundaries. Used to determine medians, quartiles, etc.
  • Bar Charts: Used for categorical or discrete data, where bars are typically separated. Height represents frequency.

Understanding the correct representation of frequency, especially with unequal class intervals using frequency density and area, is crucial for accurate data analysis and interpretation from histograms.

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Important Questions from Classification of Data

  1. A set of annual numerical data, comparable over the years, is given for the last 12 years.

    Consider the following statements:

    1. The data is best represented by a broken line graph, each corner (turning point) representing the data of one year.

    2. Such a graph depicts the chronological change and also enables one to make a short-term forecast.

    Which of the above statements is/are correct?
  2. Consider the following statements:

    Statement 1: Range is not a good measure of dispersion.

    Statement 2: Range is highly affected by the existence of extreme values.

    Which one of the following is correct in respect of the above statements?

  3. Data can be represented in which of the following forms?

    1. Textual form

    2. Tabula form

    3. Graphical form

    Select the correct answer using the code given below.
  4. Which statement of the following is incorrect?

  5. When the collected data is grouped with reference to time, we have

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