Question
Find the volume of a cylinder whose height is 21 cm and its radius is \(\tfrac{3}{5}\) of the radius of another cylinder with a volume of 317900 cm3 and a height of 14 cm. (Use \(\pi = \tfrac{22}{7}\))
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RRB NTPC 2025 Under Graduate CBT 1 Question Paper PDF (20-Jun-2026) (Shift 3)
The correct answer is
171666 cm3
Volume of the second cylinder: \(V = \pi r^2 h = 317900\), with h = 14 cm.
So \(r^2 = \dfrac{317900}{\frac{22}{7}\times14} = \dfrac{317900}{44} = 7225\), giving \(r = 85\) cm.
The first cylinder's radius is \(\tfrac{3}{5}\) of 85, i.e. \(51\) cm, with height 21 cm.
Its volume: \(\tfrac{22}{7}\times51^2\times21 = \tfrac{22}{7}\times2601\times21 = 171666\) cm3.
Hence, the volume of the cylinder is 171666 cm3.
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