Simplifying Algebraic Expression Using Identities
The problem asks for the value of the expression:
$ \frac{564 \times 564 \times 564 - 246 \times 246 \times 246}{564 \times 564 + 564 \times 246 + 246 \times 246} $
Let $a = 564$ and $b = 246$. The expression can be rewritten in terms of $a$ and $b$ as:
$ \frac{a^3 - b^3}{a^2 + ab + b^2} $
Applying the Difference of Cubes Formula
We use the algebraic identity for the difference of cubes:
$ a^3 - b^3 = (a - b)(a^2 + ab + b^2) $
Substitute this identity into the numerator of the expression:
$ \frac{(a - b)(a^2 + ab + b^2)}{a^2 + ab + b^2} $
Final Calculation
Cancel out the common term $(a^2 + ab + b^2)$ from the numerator and the denominator:
$ a - b $
Now, substitute the original values of $a$ and $b$ back:
$ 564 - 246 $
Perform the subtraction:
$ 564 - 246 = 318 $
Therefore, the value of the given expression is 318.
Similar Questions
- If $a + b + c = 10$ and $ab + bc + ca = 31$, find the value of $a^2 + b^2 + c^2$
If $a + b + c = 0$, then find the value of $\frac{(a^2+b^2+c^2)^2}{a^2b^2+b^2c^2+c^2a^2}$
- If $x^4 + \frac{1}{x^4} = 322$, then $x^3 - \frac{1}{x^3} = ?$
- If $(x + \frac{1}{x}) = 7$, then $(x - \frac{1}{x})$ is equal to:
- If $x + y + z = 0$, then the value of $\frac{x^2}{yz} + \frac{y^2}{zx} + \frac{z^2}{xy}$ is:
- What is the value of the following expression:
$(1 + x)(1 + x^2)(1 + x^4)(1 + x^8)(1 - x)$ - If $a + b + c = 17$, $abc = 168$, and $ab + bc + ca = 94$, then $a^3 + b^3 + c^3 = ?$
- If $a = \frac{b^2}{b - a}$, then the value of $a^3 + b^3$ is:
- If $ab = 10$ and $a^{2} + b^{2} = 29$, then $(a - b)^{2} = ?$
- Find the value of $\frac{(74 + 47)^2 + (74 - 47)^2}{74^2 + 47^2}$
Important Questions from Identities
If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:
- \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?
If a + b + c = 5, a 2+ b 2+ c 2= 27, a 3 + b 3 + c 3 = 125, then the value of \(\frac{abc}{5}\) is:
(999) 2- 2 2=
