The problem asks for the value of the expression:
$ \frac{564 \times 564 \times 564 - 246 \times 246 \times 246}{564 \times 564 + 564 \times 246 + 246 \times 246} $
Let $a = 564$ and $b = 246$. The expression can be rewritten in terms of $a$ and $b$ as:
$ \frac{a^3 - b^3}{a^2 + ab + b^2} $
We use the algebraic identity for the difference of cubes:
$ a^3 - b^3 = (a - b)(a^2 + ab + b^2) $
Substitute this identity into the numerator of the expression:
$ \frac{(a - b)(a^2 + ab + b^2)}{a^2 + ab + b^2} $
Cancel out the common term $(a^2 + ab + b^2)$ from the numerator and the denominator:
$ a - b $
Now, substitute the original values of $a$ and $b$ back:
$ 564 - 246 $
Perform the subtraction:
$ 564 - 246 = 318 $
Therefore, the value of the given expression is 318.
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