The problem asks us to calculate the value of a series of multiplications involving fractions and a base number. We need to find "3 times of 3 tenths of 3 hundredths of 3 thousandths of 30".
First, let's convert the fractions into mathematical terms:
The phrase "A of B" means $A \times B$. Therefore, the entire expression can be written as:
$3 \times \frac{3}{10} \times \frac{3}{100} \times \frac{3}{1000} \times 30$
Let's calculate the value step-by-step:
The value of 3 times of 3 tenths of 3 hundredths of 3 thousandths of 30 is $0.00243$.
Simplify the given expression.
$9 \times 0.9 \times 0.09 \times 0.009 \times \frac{1}{0.3} \times \frac{1}{0.03} \times \frac{1}{0.003}$
Arrange the following numbers in their increasing order.
(1) $-0.96$
(2) $0.83$
(3) $0.24$
(4) $-0.64$
(5) $0.58$
The value of \(\frac{1}{4} + \frac{{[{{(20.35)}^2} - {{(8.35)}^2}] \times 0.0175}}{{{{(1.05)}^2} + (1.05)(27.65)}}\) is:
The value of \(0.4\overline 6 + 0.7\overline {23} - 0.3\overline 9 \times 0.\overline 7 \) is:
The value of \(\frac{48.3\times[(4.95)^2+4.95\times13.25]}{[(12.55)^2-(5.65)^2]\times19.8} \) is:
Find the value of (1.6) 3 - (0.9) 3 - (0.7) 3.
What is the value of x, if \(5\left( {1 - \frac{x}{5}} \right) - (5 - x) - \frac{1}{{200}}{\rm{of (20 - x) = 0}}{\rm{.08}}\) ?