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Question

Find the HCF of 60, 148 and 382.

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

2

Understanding HCF (Highest Common Factor)

The Highest Common Factor (HCF) of a set of numbers is the largest positive integer that divides each number in the set without leaving a remainder. It is also known as the Greatest Common Divisor (GCD).

Finding the HCF helps in simplifying fractions and solving problems related to equal distribution.

Methods to Find HCF

There are several methods to find the HCF of numbers. Two common methods are:

  • Prime Factorization Method: Find the prime factors of each number and identify the common factors. The HCF is the product of the lowest powers of these common factors.
  • Division Method: Use the division algorithm repeatedly to find the HCF of two numbers, then find the HCF of the result and the next number, and so on.

Calculating the HCF of 60, 148, and 382 using Prime Factorization

Let's use the prime factorization method to find the HCF of 60, 148, and 382 step-by-step.

Step 1: Find the prime factorization of each number.

We break down each number into its prime factors:

  • Prime factorization of 60: $\qquad 60 = 2 \times 30 = 2 \times 2 \times 15 = 2^2 \times 3^1 \times 5^1$
  • Prime factorization of 148: $\qquad 148 = 2 \times 74 = 2 \times 2 \times 37 = 2^2 \times 37^1$
  • Prime factorization of 382: $\qquad 382 = 2 \times 191 = 2^1 \times 191^1$ (Note: 191 is a prime number)

We can summarize the prime factorizations in a table:

NumberPrime Factorization
60$2^2 \times 3^1 \times 5^1$
148$2^2 \times 37^1$
382$2^1 \times 191^1$

Step 2: Identify common prime factors.

Look for the prime factors that appear in the factorization of all three numbers (60, 148, and 382).

  • The prime factor 2 is present in the factorization of 60 ($2^2$), 148 ($2^2$), and 382 ($2^1$).
  • The prime factor 3 is only present in 60.
  • The prime factor 5 is only present in 60.
  • The prime factor 37 is only present in 148.
  • The prime factor 191 is only present in 382.

The only common prime factor among 60, 148, and 382 is 2.

Step 3: Find the lowest power of each common prime factor.

For the common prime factor 2, find the smallest exponent it has across all the numbers:

  • In 60, the power of 2 is 2 ($2^2$).
  • In 148, the power of 2 is 2 ($2^2$).
  • In 382, the power of 2 is 1 ($2^1$).

The lowest power of the common prime factor 2 is 1 ($2^1$).

Step 4: Calculate the HCF.

The HCF is the product of the lowest powers of all the common prime factors.

In this case, the only common prime factor is 2, and its lowest power is $2^1$.

HCF $= 2^1 = 2$

Conclusion: HCF of 60, 148, and 382

The Highest Common Factor (HCF) of 60, 148, and 382 is 2.

Revision Table: Key Concepts for HCF Calculation

ConceptDescriptionHow to Find
HCF (Highest Common Factor)The largest integer that divides two or more numbers without remainder.Prime Factorization or Division Method.
Prime NumberA natural number greater than 1 that has no positive divisors other than 1 and itself (e.g., 2, 3, 5, 7, 11, 191...).Check for divisibility by smaller prime numbers.
Prime FactorizationExpressing a composite number as a product of its prime numbers.Repeated division by prime numbers until the quotient is 1.

Additional Information: HCF Applications and Properties

The concept of HCF is a fundamental building block in number theory and has practical applications:

  • Simplifying Fractions: To reduce a fraction to its simplest form, divide both the numerator and the denominator by their HCF.
  • Problem Solving: HCF is useful in real-world scenarios involving dividing quantities into equal parts or arranging items in rows or groups of the largest possible size.
  • Relationship with LCM: For any two positive integers 'a' and 'b', the product of their HCF and Least Common Multiple (LCM) is equal to the product of the numbers: $\qquad \text{HCF}(a, b) \times \text{LCM}(a, b) = a \times b$

Understanding how to find the HCF strengthens skills in arithmetic and algebraic manipulations.

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Similar Questions

  1. A and B are two prime numbers such that A > B and their LCM is 209. The value of B 2 –  A is:

  2. Choose the option in which the numbers are in correct ascending order.

  3. The HCF of two numbers is 17 and the other two factors of their LCM are 11 and 19. The smaller of the two numbers is:

  4. The HCF of two numbers is 8 and their LCM is 2520. If one of the numbers is 56, then the other number is:

  5. The LCM of 1.2 and 2.7 is:

  6. Find the HCF of 4.08 and 6.63.

  7. The HCF of three numbers 98, 175 and 210 will be:

  8. Determine the LCM of two numbers if their HCF is 9 and their ratio is 14 : 19.

  9. If the highest common factor (HCF) of x and y is 15, then the HCF of 36x2 - 81y2 and 81x2 - 9y2 is divisible by ______.

  10. The sum of and difference between the LCM and HCF of two numbers are 512 and 496, respectively. If one number is 72, then the other number is:


Important Questions from LCM and HCF

  1. The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:

  2. Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.

  3. Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?

  4. The sum of two numbers is 1215 and their HCF is 81. How many such pairs of numbers can be formed?

  5. The LCM of two numbers in 48. Their ratio is 2:3 What is the sum of the numbers?

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