The HCF of two numbers is 17 and the other two factors of their LCM are 11 and 19. The smaller of the two numbers is:
187
The problem involves finding the smaller of two numbers given their Highest Common Factor (HCF) and information about their Least Common Multiple (LCM). We need to use the fundamental relationship between two numbers, their HCF, and their LCM.
For any two positive integers, say 'a' and 'b', the product of the numbers is equal to the product of their HCF and LCM.
\( a \times b = \text{HCF}(a, b) \times \text{LCM}(a, b) \)
Another important concept is that if the HCF of two numbers 'a' and 'b' is \(h\), then the numbers can be expressed as \(a = hx\) and \(b = hy\), where \(x\) and \(y\) are integers that are coprime (their HCF is 1). In this case, their LCM is given by \( \text{LCM}(a, b) = hxy \).
We are given:
The LCM of two numbers is the product of their HCF and the other coprime factors from each number. The statement "other two factors of their LCM are 11 and 19" implies that the LCM can be written as HCF \( \times \) 11 \( \times \) 19. This is because 11 and 19 are given as factors of the LCM besides the HCF, and they must represent the \(x\) and \(y\) parts from the formula \( \text{LCM} = hxy \).
Since 11 and 19 are prime numbers, they are coprime. Therefore, we can consider these as the coprime factors \(x\) and \(y\).
Using the representation of the numbers \(a = hx\) and \(b = hy\), we can find the two numbers.
The two numbers are:
Let's calculate their values:
| 10 | 7 | |
|---|---|---|
| 11 | 110 | 77 |
\(17 \times 11 = 110 + 77 = 187\)
| 10 | 7 | |
|---|---|---|
| 19 | 190 | 133 |
\(17 \times 19 = 190 + 133 = 323\)
So the two numbers are 187 and 323.
Comparing the two numbers, 187 and 323, the smaller number is 187.
Let's quickly verify our answer:
The calculations match the given information, and the smaller number is 187.
| Concept | Definition | Property | Example |
|---|---|---|---|
| HCF (Highest Common Factor) | Largest positive integer that divides two or more numbers without leaving a remainder. | HCF of \(ax, ay\) is \(a \times\) HCF(\(x, y\)) | HCF(12, 18) = 6 |
| LCM (Least Common Multiple) | Smallest positive integer that is a multiple of two or more numbers. | For numbers \(a, b\), \(a \times b = \text{HCF}(a, b) \times \text{LCM}(a, b)\) | LCM(12, 18) = 36 |
| Relationship | Product of numbers = Product of HCF and LCM | If \(a=hx, b=hy\) where HCF(\(x,y\))=1, then LCM(\(a,b\)) = \(hxy\) | Numbers 12 (\(6\times2\)) and 18 (\(6\times3\)). HCF=6, \(x=2, y=3\). LCM = \(6\times2\times3 = 36\). \(12 \times 18 = 216\), \(6 \times 36 = 216\). |
The prime factorization method is often used to find the HCF and LCM of numbers. Let's consider our numbers 187 and 323.
To find the HCF, we look for common prime factors and take the lowest power:
To find the LCM, we take all prime factors from both numbers and use the highest power:
Notice that the LCM (\(17 \times 11 \times 19\)) consists of the HCF (17) and the 'other' factors (11 and 19), as stated in the problem. This confirms our approach was correct.
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