The Highest Common Factor (HCF) is the largest number that divides two or more numbers without leaving a remainder. We can find the HCF using the prime factorization method.
Find the prime factors for each number:
Identify the prime factors that are common to all three numbers:
Multiply the common prime factors, taking the lowest power of each common factor present in any of the factorizations:
HCF = \(2^1 \times 3^1 = 2 \times 3 = 6\).
The HCF of 24, 36, and 102 is 6.
The HCF of the numbers 310, 208, and 180 is:
If LCM(27, n) = 54, and HCF(27, n) = 9, then the value of n is:
The highest common factor of a set of coprime numbers is equal to:
Two numbers are in ratio 3 : 2. Their LCM and HCF are 24 and 4, respectively. Find the greater number.
The LCM of two numbers is 84. If the numbers are in the ratio 2 : 3, then the sum of the numbers is:
What is the least positive number that can be added to 2488 so that it is completely divisible by 3, 4, 5, and 6?
The HCF of two numbers is 9 and their LCM is 252. The sum of numbers is:
The HCF and LCM of two numbers are 12 and 72, respectively. If the ratio of the two numbers is 2 ∶ 3, then the larger of the two numbers is:
Find the greatest number that will divide 43, 91 and 183 so as to leave the same remainder in each case.
Joseph visits the club on every 5 th day, Harsh visits on every 24 th day, while Sumit visits on every 9 th day. If all three of them met at the club on a Sunday, then on which day will all three of them meet again?
What is the least number which when divided by 12,20 and 24 leaves in each case a remainder of 8?
Which of the following is a pair of co-primes?