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Question

Find the HCF of 24, 36 and 102.

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is
6

Finding HCF of 24, 36, and 102

The Highest Common Factor (HCF) is the largest number that divides two or more numbers without leaving a remainder. We can find the HCF using the prime factorization method.

Step 1: Prime Factorization

Find the prime factors for each number:

  • 24: \(2 \times 2 \times 2 \times 3 = 2^3 \times 3\)
  • 36: \(2 \times 2 \times 3 \times 3 = 2^2 \times 3^2\)
  • 102: \(2 \times 3 \times 17\)

Step 2: Identify Common Factors

Identify the prime factors that are common to all three numbers:

  • Common factor: 2
  • Common factor: 3

Step 3: Calculate HCF

Multiply the common prime factors, taking the lowest power of each common factor present in any of the factorizations:

  • The lowest power of 2 common to all is \(2^1\).
  • The lowest power of 3 common to all is \(3^1\).

HCF = \(2^1 \times 3^1 = 2 \times 3 = 6\).

Conclusion

The HCF of 24, 36, and 102 is 6.

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  3. A number is three times another number and their HCF is 8. What is the sum of the squares of the numbers?

  4. The HCF of 2091, 3485 and 4879 is x. The sum of the digits of x is:

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