All Exams Test series for 1 year @ ₹349 only
Question

Evaluate \(23^3 + (-11)^3 + (-12)^3\)

This question was previously asked in
RRB NTPC 2025 Graduate CBT 2 Question Paper PDF (10-Jul-2026) (Shift 1)
The correct answer is

9108

Compute each cube: \(23^3=12167,\ (-11)^3=-1331,\ (-12)^3=-1728\).

Sum: \(12167-1331-1728 = 9108\).

Hence, the value of the expression is 9108.

Was this answer helpful?

Similar Questions

  1. If $a + b + c = 10$ and $ab + bc + ca = 31$, find the value of $a^2 + b^2 + c^2$
  2. If $a + b + c = 0$, then find the value of $\frac{(a^2+b^2+c^2)^2}{a^2b^2+b^2c^2+c^2a^2}$

  3. If $x^4 + \frac{1}{x^4} = 322$, then $x^3 - \frac{1}{x^3} = ?$
  4. If $(x + \frac{1}{x}) = 7$, then $(x - \frac{1}{x})$ is equal to:
  5. If $x + y + z = 0$, then the value of $\frac{x^2}{yz} + \frac{y^2}{zx} + \frac{z^2}{xy}$ is:
  6. What is the value of the following expression:

    $(1 + x)(1 + x^2)(1 + x^4)(1 + x^8)(1 - x)$
  7. If $a + b + c = 17$, $abc = 168$, and $ab + bc + ca = 94$, then $a^3 + b^3 + c^3 = ?$
  8. If $a = \frac{b^2}{b - a}$, then the value of $a^3 + b^3$ is:
  9. If $ab = 10$ and $a^{2} + b^{2} = 29$, then $(a - b)^{2} = ?$
  10. Find the value of $\frac{(74 + 47)^2 + (74 - 47)^2}{74^2 + 47^2}$

Important Questions from Identities

  1. If \(2x + { {1} \over 3x}= 5, x ≠ 0\) , then what is the value of  \(27x^3+{{1} \over 8x^3}\) ?

  2. If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:

  3. \(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)
  4. \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
  5. If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?

Need Expert Advice?
Upcoming Exams
RRB Technician
October 06, 2026
RRB JE
October 27, 2026
RRB ALP
November 03, 2026
Test Series
RRB NTPC img
Railways
RRB NTPC Under Graduate 2026 New Mock Test Series
1580 Tests 2 Tests Free
544 Attempts
4.3(498)
English, Hindi, Telugu +7 More

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App