Evaluate \(23^3 + (-11)^3 + (-12)^3\)
9108
Compute each cube: \(23^3=12167,\ (-11)^3=-1331,\ (-12)^3=-1728\).
Sum: \(12167-1331-1728 = 9108\).
Hence, the value of the expression is 9108.
If $a + b + c = 0$, then find the value of $\frac{(a^2+b^2+c^2)^2}{a^2b^2+b^2c^2+c^2a^2}$
(x - y) 3+ (y - z) 3+ (z - x) 3= ?
If \(x + \left( {\frac{1}{x}} \right) = 12\) and \({x^2} - \frac{1}{{{x^2}}} = 50\) , then the value of \({x^4} - \frac{1}{{{x^4}}} \) is:
If x satisfies the equation x 2 - 2x + 1 = 0, then the value of \(\rm x^3 - \frac{1}{x^3}\) is:
If x + y = 5 and xy = 6, then find x 3+ y 3