Determine the values of current amplification factor \((\beta)\) of two different transistors having \(\alpha_1 = 0.99\) and \(\alpha_2 = 0.98\) :
99 and 49 respectively
Formula: \(\beta = \frac{\alpha}{1 - \alpha}\)
Transistor 1: \(\beta_1 = \frac{0.99}{1 - 0.99} = \frac{0.99}{0.01} = 99\)
Transistor 2: \(\beta_2 = \frac{0.98}{1 - 0.98} = \frac{0.98}{0.02} = 49\)
Check: \(\alpha = \frac{\beta}{1 + \beta} = \frac{49}{50} = 0.98\), which matches the given value.
Hence, 99 and 49 respectively.
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.................... is a client server application that identifies each host on the internet with a unique user-friendly name.
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Codes:
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(i) Machine language
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