This problem involves finding the Least Common Multiple (LCM) of the ringing intervals to determine when the phones will ring together again.
To find when they will ring together, we need the LCM of 20, 24, and 30.
The LCM is $120$ seconds.
Convert the interval back into minutes:
$ 120 \text{ seconds} = \frac{120}{60} \text{ minutes} = 2 \text{ minutes} $
Add this interval to the time they last rang together:
Last ring time: 11:25 a.m.
Interval: 2 minutes
Next ring time: $ 11:25 \text{ a.m.} + 2 \text{ minutes} = 11:27 \text{ a.m.} $
Therefore, the phones will next ring together at 11:27 a.m.
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?