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Let the distance between A and B be \(d\) km.
Time taken to go from A to B at 40 km/hr is \(t_1 = \frac{d}{40}\) hours.
Time taken to return from B to A at 10 km/hr is \(t_2 = \frac{d}{10}\) hours.
Total distance covered = \(d + d = 2d\) km.
Total time taken = \(t_1 + t_2 = \frac{d}{40} + \frac{d}{10} = \frac{d + 4d}{40} = \frac{5d}{40} = \frac{d}{8}\) hours.
Average speed = \(\frac{\text{Total distance}}{\text{Total time}} = \frac{2d}{\frac{d}{8}} = \frac{2d \times 8}{d} = 16\) km/hr.
Therefore, the average speed of the train during the two-way journey is 16 km/hr.
Similar Questions
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Important Questions from Average Speed
A person covers a certain distance at the speed of 60 kmph and returns to the starting point at a speed of 40 kmph . Find the average speed (in km/hour) of the person for the whole journey.
A train runs at a speed of 28 kmph for 4 hours and 30 kmph for 5 hours and the remaining 40 kms in one hour. What is the average speed per hour?
Kapil travels for 4.5 hours at a speed of 50 km / h and 7.5 hours at a speed of 70 km / h. At the end of it, he finds that he covered only 6/7 of the total distance. At what average speed should he travel so that the remaining distance traveled in 5 hours?
A car has to cover 125 kms in 5 hours. What will be the average speed of the car if it has covered 90 kms in the first 3 hours?
A scooter from P to Q travels at 40 km/h and from Q to P at 30 km/h. What is the average speed of the scooter?
