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Question

A car travels 120 km at 60 km/h, then 200 km at 80 km/h, but during the second segment, it experiences a total stoppage time of 20 minutes due to traffic. After that, it covers the final 150 km at 100 km/h. What is the average speed (in km/h, rounded off to one decimal place) of the car for the entire journey including stoppage times?

This question was previously asked in
RRB ALP 2025 CBT 2 Wiremen Question Paper (28-Jul-2026) (Shift 2)
The correct answer is
74.2

The problem asks for the average speed of a car over a multi-segment journey, including a stoppage time. Average speed is calculated as Total Distance divided by Total Time.

Calculating Total Distance

The total distance is the sum of the distances covered in each segment:

  • Segment 1: 120 km
  • Segment 2: 200 km
  • Segment 3: 150 km

Total Distance = \(120 \text{ km} + 200 \text{ km} + 150 \text{ km} = 470 \text{ km}\)

Calculating Total Time

First, calculate the time taken for each segment using the formula: Time = Distance / Speed.

  • Segment 1 Time:

    Time = \(\frac{120 \text{ km}}{60 \text{ km/h}} = 2 \text{ hours}\)

  • Segment 2 Time:

    Time = \(\frac{200 \text{ km}}{80 \text{ km/h}} = 2.5 \text{ hours}\)

  • Segment 3 Time:

    Time = \(\frac{150 \text{ km}}{100 \text{ km/h}} = 1.5 \text{ hours}\)

Next, account for the stoppage time during the second segment. Convert minutes to hours:

Stoppage Time = \(20 \text{ minutes} = \frac{20}{60} \text{ hours} = \frac{1}{3} \text{ hours}\)

Now, sum all the times to find the total duration of the journey:

Total Time = (Segment 1 Time) + (Segment 2 Time) + (Segment 3 Time) + (Stoppage Time)

Total Time = \(2 \text{ hours} + 2.5 \text{ hours} + 1.5 \text{ hours} + \frac{1}{3} \text{ hours}\)

Total Time = \(6 \text{ hours} + \frac{1}{3} \text{ hours} = \frac{18}{3} \text{ hours} + \frac{1}{3} \text{ hours} = \frac{19}{3} \text{ hours}\)

Calculating Average Speed

Use the formula for average speed:

Average Speed = \(\frac{\text{Total Distance}}{\text{Total Time}}\)

Average Speed = \(\frac{470 \text{ km}}{\frac{19}{3} \text{ hours}}\)

Average Speed = \(\frac{470 \times 3}{19} \text{ km/h}\)

Average Speed = \(\frac{1410}{19} \text{ km/h}\)

Average Speed \(\approx 74.2105... \text{ km/h}\)

Rounding to one decimal place, the average speed is 74.2 km/h.

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Similar Questions

  1. A person drove at 53 kmph for 2.5 hours, then increased his speed by 28 kmph, and reached the destination in another hour. Find the average speed (in kmph) of the person during the entire journey.

Important Questions from Average Speed

  1. A car covers the first 41 km of its journey in 45 min and covers the remaining 23 km in 35 min. What is the average speed (in m/sec) of the car?

  2. Akhil drives a car from his home to office at an average speed of 50 km/h and reaches office 10 minutes early. But one day due to some problem with the car, he could drive at an average speed of 30 km/h only and reached office 10 minutes late. How far is his office from home ?

  3. During a flight of 900 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 300 km/h and the time of flight increased by 30 min. The original duration of the flight was :

  4. If a man travels from A to B at a speed of 50 km/h and returns by increasing his speed by 40%, then find his average speed (to 2 decimal places) for both the trips.

  5. A man travels a distance of 420 km by train which moves at the speed of 75 km/h and returns back by car at the speed of 50 km/h. Find his average speed for the whole journey.

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