The problem asks for the average speed of a car over a multi-segment journey, including a stoppage time. Average speed is calculated as Total Distance divided by Total Time.
The total distance is the sum of the distances covered in each segment:
Total Distance = \(120 \text{ km} + 200 \text{ km} + 150 \text{ km} = 470 \text{ km}\)
First, calculate the time taken for each segment using the formula: Time = Distance / Speed.
Time = \(\frac{120 \text{ km}}{60 \text{ km/h}} = 2 \text{ hours}\)
Time = \(\frac{200 \text{ km}}{80 \text{ km/h}} = 2.5 \text{ hours}\)
Time = \(\frac{150 \text{ km}}{100 \text{ km/h}} = 1.5 \text{ hours}\)
Next, account for the stoppage time during the second segment. Convert minutes to hours:
Stoppage Time = \(20 \text{ minutes} = \frac{20}{60} \text{ hours} = \frac{1}{3} \text{ hours}\)
Now, sum all the times to find the total duration of the journey:
Total Time = (Segment 1 Time) + (Segment 2 Time) + (Segment 3 Time) + (Stoppage Time)
Total Time = \(2 \text{ hours} + 2.5 \text{ hours} + 1.5 \text{ hours} + \frac{1}{3} \text{ hours}\)
Total Time = \(6 \text{ hours} + \frac{1}{3} \text{ hours} = \frac{18}{3} \text{ hours} + \frac{1}{3} \text{ hours} = \frac{19}{3} \text{ hours}\)
Use the formula for average speed:
Average Speed = \(\frac{\text{Total Distance}}{\text{Total Time}}\)
Average Speed = \(\frac{470 \text{ km}}{\frac{19}{3} \text{ hours}}\)
Average Speed = \(\frac{470 \times 3}{19} \text{ km/h}\)
Average Speed = \(\frac{1410}{19} \text{ km/h}\)
Average Speed \(\approx 74.2105... \text{ km/h}\)
Rounding to one decimal place, the average speed is 74.2 km/h.
A car covers the first 41 km of its journey in 45 min and covers the remaining 23 km in 35 min. What is the average speed (in m/sec) of the car?
Akhil drives a car from his home to office at an average speed of 50 km/h and reaches office 10 minutes early. But one day due to some problem with the car, he could drive at an average speed of 30 km/h only and reached office 10 minutes late. How far is his office from home ?
During a flight of 900 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 300 km/h and the time of flight increased by 30 min. The original duration of the flight was :
If a man travels from A to B at a speed of 50 km/h and returns by increasing his speed by 40%, then find his average speed (to 2 decimal places) for both the trips.
A man travels a distance of 420 km by train which moves at the speed of 75 km/h and returns back by car at the speed of 50 km/h. Find his average speed for the whole journey.