All Exams Test series for 1 year @ ₹349 only
Question

A scooter from P to Q travels at 40 km/h and from Q to P at 30 km/h. What is the average speed of the scooter?

The correct answer is

240/7 km/h

Understanding Average Speed

The question asks for the average speed of a scooter that travels from point P to point Q and then back from Q to P at different speeds. It's important to remember that average speed is not simply the average of the two speeds. It is calculated as the total distance traveled divided by the total time taken.

The scooter travels from P to Q and then from Q back to P. This means the distance covered in both directions is the same. Let's assume the distance between point P and point Q is d kilometers.

Calculating Time Taken for Each Leg

The scooter travels from P to Q at a speed of 40 km/h. The time taken for this journey ($t_1$) can be calculated using the formula: Time = Distance / Speed.

$\qquad t_1 = \frac{\text{Distance (P to Q)}}{\text{Speed (P to Q)}} = \frac{d}{40}$ hours

The scooter travels from Q to P at a speed of 30 km/h. The time taken for this return journey ($t_2$) is:

$\qquad t_2 = \frac{\text{Distance (Q to P)}}{\text{Speed (Q to P)}} = \frac{d}{30}$ hours

Calculating Total Distance and Total Time

The total distance traveled by the scooter for the round trip (P to Q and Q to P) is the sum of the distance in each direction:

$\qquad \text{Total Distance} = \text{Distance (P to Q)} + \text{Distance (Q to P)} = d + d = 2d$ kilometers

The total time taken for the entire journey is the sum of the time taken for each leg:

$\qquad \text{Total Time} = t_1 + t_2 = \frac{d}{40} + \frac{d}{30}$ hours

To add the fractions for total time, we find a common denominator, which is 120:

$\qquad \text{Total Time} = \frac{d \times 3}{40 \times 3} + \frac{d \times 4}{30 \times 4} = \frac{3d}{120} + \frac{4d}{120} = \frac{3d + 4d}{120} = \frac{7d}{120}$ hours

Calculating Average Speed

Now we can calculate the average speed using the formula: Average Speed = Total Distance / Total Time.

$\qquad \text{Average Speed} = \frac{2d}{\frac{7d}{120}}$

To divide by a fraction, we multiply by its reciprocal:

$\qquad \text{Average Speed} = 2d \times \frac{120}{7d}$

The 'd' terms cancel out:

$\qquad \text{Average Speed} = \frac{2 \times 120}{7} = \frac{240}{7}$ km/h

Alternatively, when an object travels the same distance in two parts of a journey with different speeds ($v_1$ and $v_2$), the average speed can be calculated directly using the formula:

$\qquad \text{Average Speed} = \frac{2 v_1 v_2}{v_1 + v_2}$

Substituting the given speeds, $v_1 = 40$ km/h and $v_2 = 30$ km/h:

$\qquad \text{Average Speed} = \frac{2 \times 40 \times 30}{40 + 30} = \frac{2400}{70}$

Simplifying the fraction:

$\qquad \text{Average Speed} = \frac{240}{7}$ km/h

Both methods yield the same result for the average speed of the scooter.

Final Answer

The average speed of the scooter for the round trip is $\frac{240}{7}$ km/h.

Was this answer helpful?

Important Questions from Average Speed

  1. A person covers a certain distance at the speed of 60 kmph and returns to the starting point at a speed of 40 kmph . Find the average speed (in km/hour) of the person for the whole journey.

  2. A train runs at a speed of 28 kmph for 4 hours and 30 kmph for 5 hours and the remaining 40 kms in one hour. What is the average speed per hour?

  3. Kapil travels for 4.5 hours at a speed of 50 km / h and 7.5 hours at a speed of 70 km / h. At the end of it, he finds that he covered only 6/7 of the total distance. At what average speed should he travel so that the remaining distance traveled in 5 hours?

  4. An express train travelled at an average speed of 100 km/hr, stopping for 3 minutes after every 75 km. How long it take to reach its destination 600 km from the starting point?

  5. A car has to cover 125 kms in 5 hours. What will be the average speed of the car if it has covered 90 kms in the first 3 hours?

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App