To find the average speed for the entire journey, we need to calculate the total distance traveled and divide it by the total time taken.
The journey consists of four segments:
Total Distance = Distance(A to B) + Distance(B to C) + Distance(C to B) + Distance(B to A)
\( \text{Total Distance} = 180 \text{ km} + 240 \text{ km} + 240 \text{ km} + 180 \text{ km} = 840 \text{ km} \)
Time is calculated using the formula: Time = Distance / Speed.
Total Time = Sum of times for all segments.
\( \text{Total Time} = T_{AB} + T_{BC} + T_{CB} + T_{BA} = 4 \text{ h} + 4 \text{ h} + 6 \text{ h} + 6 \text{ h} = 20 \text{ hours} \)
Average speed is defined as Total Distance divided by Total Time.
\( \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} \)
\( \text{Average Speed} = \frac{840 \text{ km}}{20 \text{ hours}} = 42 \text{ km/h} \)
The average speed for the entire journey is 42 km/h.
A car covers the first 41 km of its journey in 45 min and covers the remaining 23 km in 35 min. What is the average speed (in m/sec) of the car?
Akhil drives a car from his home to office at an average speed of 50 km/h and reaches office 10 minutes early. But one day due to some problem with the car, he could drive at an average speed of 30 km/h only and reached office 10 minutes late. How far is his office from home ?
During a flight of 900 km, an aircraft was slowed down due to bad weather. Its average speed for the trip was reduced by 300 km/h and the time of flight increased by 30 min. The original duration of the flight was :
If a man travels from A to B at a speed of 50 km/h and returns by increasing his speed by 40%, then find his average speed (to 2 decimal places) for both the trips.
A man travels a distance of 420 km by train which moves at the speed of 75 km/h and returns back by car at the speed of 50 km/h. Find his average speed for the whole journey.