Statement Analysis

The given statement provides a series of relationships between different variables:

• $C < A ≤ T = D ≥ O$
• $G ≥ D < S$
• $T ≥ A$ (This is consistent with $A ≤ T$ from the first part)

Let's combine these to understand the overall structure:

• From $C < A ≤ T$ and $T = D$, we establish $C < A ≤ T = D$.
• Adding $D ≥ O$ gives $C < A ≤ T = D ≥ O$.
• Adding $G ≥ D$ gives $C < A ≤ T = D ≤ G$.
• The relation $D < S$ is also given but does not influence the conclusions regarding C, A, O, and G.

Conclusion I Evaluation: A ≤ O

From the analysis, we have $A ≤ T = D$ and $D ≥ O$.

This means A is less than or equal to D, and D is greater than or equal to O. However, there's no fixed relationship between A and O based on these inequalities alone. A could be less than, equal to, or greater than O.

For instance:

• If T=D=5, A=3, and O=7, then $A < O$.
• If T=D=5, A=6, and O=3, then $A > O$.

Since $A > O$ is possible, Conclusion I ($A ≤ O$) is not necessarily true.

Conclusion II Evaluation: C < G

The combined chain of inequalities derived from the statement is $C < A ≤ T = D ≤ G$.

This chain directly shows that C is strictly less than A, which is less than or equal to T, which equals D, which is less than or equal to G.

Therefore, it logically follows that $C < G$.

Conclusion II is true.

Final Determination

Based on the analysis:

• Conclusion I ($A ≤ O$) is not necessarily true.
• Conclusion II ($C < G$) is necessarily true.

Hence, only Conclusion II follows from the given statement.