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Question

Find the missing number in the series:
 

867
91311
37?

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

5

The pattern in the given number series is based on the difference between the numbers in each row and column. Let's analyze it step-by-step:

867
91311
37?

Analyzing Columns:

  • Column 1: The difference between 9 and 8 is 1, and the difference between 3 and 9 is -6.
  • Column 2: The difference between 13 and 6 is 7, and the difference between 7 and 13 is -6.

Notice that the difference between the second and first row in each column is consistent (-6). This suggests a consistent pattern across columns. Let's see if this holds for the third column.

Analyzing Rows:

  • Row 1: 8 - 6 = 2, 6 - 7 = -1
  • Row 2: 9 - 13 = -4, 13 - 11 = 2

Row-wise differences don't seem to be consistent.

Focusing on the Consistent Column Difference:

Since the difference between the second and first row in each column is -6, we can apply this to the third column:

Let 'x' be the missing number. Then, 7 - x = -6. Solving for x, we get x = 7 + 6 = 13.

However, 13 is not among the options. Let's re-examine our approach. The column difference observation might be misleading.

Let's look at another possible pattern. Observe that in each row, the sum of the first two numbers minus the third number equals a constant. Let's verify.

Row 1: 8 + 6 - 7 = 7

Row 2: 9 + 13 - 11 = 11

This pattern is not consistent. Let's try another approach. Let's analyze the difference between consecutive numbers in each row:

Row 1: 8 - 6 = 2; 6 - 7 = -1

Row 2: 9 - 13 = -4; 13 - 11 = 2

No clear pattern emerges.

Let's reconsider the column differences. In column 1, 8 + 1 = 9, and 9 -6 =3. In column 2, 6 + 7 = 13, and 13 - 6 = 7. If we apply this to column 3, 7 + 6 = 13, and 13 - 6 = 7. This does not yield a solution in the options.

Upon further examination and considering the options provided, let's try a different strategy. There seems to be no consistent arithmetic pattern across all the numbers. Trying to find a pattern may be unreliable given the limited data points. The only way to arrive at a solution is by trial and error considering the options provided. The only option that creates any remotely consistent pattern (although still flawed) is 5.

Therefore, given the options provided, 5 is the most plausible answer although the underlying mathematical rule remains somewhat obscure.

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Important Questions from Mathematical Inequalities

  1. Directions: In the following question assuming the given statements to be true, find which of the conclusion(s) among given conclusions is/are definitely true and then give your answers accordingly.

    Statement:

    Y ≥ C < O ≥ F < R = B

    Conclusions:

    I. B > F

    II. R > C

  2. Directions: In each of the following questions assuming the given statement to be true, find which of the conclusions among given conclusions is / are definitely true and then give your answers accordingly.

    Statement: E < U > L > K ≤ T = H ≤ Q

    Conclusions:

    I. U > H

    II. T ≤ Q

  3. Directions: In the following question assuming the given statements to be True, find which of the conclusion among given conclusions is/are definitely true and then give your answers accordingly.

    Statements: Y > U ≥ Z ≥ K = X ≤ B ≤ A

    Conclusions:

    I. U = X

    II. U > X

  4. Directions: In each of the following questions assuming the given statement to be true, find which of the conclusions among given conclusions is/are definitely true and then give your answers accordingly.

    Statement: S > L < P = T ≥ V > R

    Conclusions:

    I. P > R

    II. S > V

  5. In the question given, relations between different elements are shown in the statements. These statements are followed by two conclusions. Find out which of the given conclusions follow(s) the given statements and select the correct alternative from the given choices.

    Statement:

    L ≥ M = N < O, P < Q ≥ R = S ≥ L

    Conclusion:

    I. Q > M

    II. N = Q

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