A Si n-p-n bipolar transistor has the following parameters collector current \(I_c = 6\) mA, common emitter current gain factor \(h_{FE} = 120\), operational temperature \(T = 300^\circ K\). Determine the mutual conductance of small signal transistor.
0.23 mho
Formula: \(g_m = \frac{I_C}{V_T}\), \(V_T = \frac{kT}{q}\)
\(V_T = \frac{1.38 \times 10^{-23} \times 300}{1.6 \times 10^{-19}} \approx 0.0259\) V
\(g_m = \frac{6 \times 10^{-3}}{0.0259} \approx 0.2317\) mho
\(h_{FE}\) does not enter \(g_m\); it only fixes \(r_\pi = \frac{h_{FE}}{g_m} = \frac{120}{0.2317} \approx 518\ \Omega\).
Hence, 0.23 mho.
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