A regular octagonal fountain has a circumradius of 10 m. Find the approximate length of each side.
7.65 m
For a regular polygon with n sides and circumradius R, each side length is \(s = 2R\sin\left(\frac{180^\circ}{n}\right)\).
Here the octagon has n = 8 and R = 10 m, so \(s = 2 \times 10 \times \sin\left(\frac{180^\circ}{8}\right)\).
The angle is \(\frac{180^\circ}{8} = 22.5^\circ\), and \(\sin 22.5^\circ \approx 0.3827\).
So \(s = 20 \times 0.3827 \approx 7.65\) m.
Hence, each side of the octagonal fountain is approximately 7.65 m.
Calculate the area of the triangle whose sides are 8 cm, 9 cm and 13 cm. (Rounded up to two decimal places)