A real, inverted and diminished image of an object is formed by a convex lens. At which position is the object placed?
Beyond 2F
For a convex lens, an object placed beyond 2F gives an image between F and 2F on the other side.
That image is real, inverted and diminished (smaller than the object).
At 2F the image is the same size, between F and 2F it is enlarged, and at F it forms at infinity.
Hence, the answer is Beyond 2F.
Similar Questions
Which of the following is NOT the correct use of a concave mirror?
The image formed by a concave lens for an object at infinity is:
An object is placed at a distance of 40 cm from a convex lens of focal length 10 cm, such that an image is formed at a distance of X cm from the lens. What is the value of X?
When a parallel beam of light passes through a convex lens, after refraction it:
An image is formed at a distance of 30 cm from a convex mirror when the object is placed 40 cm from the mirror. The magnification produced by the mirror will be _______.
A science fair project uses a convex mirror to monitor a hallway. If a person stands at various distances from the mirror, what remains constant about the images formed, regardless of their position?
A student observes that the image formed by a lens is twice the size of the object and is real. Where is the object placed relative to the lens?
How is the object distance measured in the sign convention for spherical lenses?
The magnification of a concave mirror is −1. Which of the following statements is correct about the position of the object?
The power of a lens is given as the reciprocal of its:
Important Questions from Refraction and Reflection
A convex lens of focal length f will form a magnified real image of an object, if the object is placed.
A ray of light travelling in the direction \(\frac{1}{2} (\hat i + \sqrt 3 \hat j)\) is incident on a plane mirror. After reflection it travels along the direction \(\frac{1}{2} (\hat i - \sqrt 3 \hat j)\) The angle of incidence is:
Twinkling of stars is due to atmospheric
An optical fibre has a core material of refractive index of 1.55 and cladding material of refractive index of 1.50. The numerical aperture of the fibre is
- The refracting angle of a prism is $A$. The refractive index of the material of the prism is $\frac{1+\cos A}{\sin A}$. The angle of minimum deviation is:
