A traffic surveillance camera uses a convex mirror with a radius of curvature of 2 m. Where will the image of a car located 3 m from the mirror appear?
0.75 m behind the mirror
For a convex mirror the focus lies behind the mirror, so with R = 2 m the focal length is f = R/2 = +1 m, and the car stands in front of the mirror at u = −3 m.
Applying the mirror formula \(\frac{1}{v}+\frac{1}{u}=\frac{1}{f}\): \(\frac{1}{v}=\frac{1}{1}-\frac{1}{-3}=1+\frac{1}{3}=\frac{4}{3}\).
So v = 3/4 = 0.75 m, and the positive sign places the image behind the mirror — the erect, diminished virtual image a convex mirror always forms.
Hence, the answer is 0.75 m behind the mirror.
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Important Questions from Refraction and Reflection
- How can you identify a concave and a convex mirror based on the direction of their reflecting surfaces?
- Stars appear to twinkle in the night sky because ______.
What type of image is always formed by a concave lens, no matter where the object is placed?
- Which of the following is NOT caused by atmospheric refraction?
- According to the sign convention, the height of an erect image formed by a mirror is taken as:
