The ratio of two numbers is \(3:4\) and their HCF is 7. Their LCM is:
84
Since the ratio of the numbers is \(3:4\) and their HCF is 7, the numbers are \(3 \times 7 = 21\) and \(4 \times 7 = 28\).
LCM \(= \dfrac{\text{product of the numbers}}{\text{HCF}} = \dfrac{21 \times 28}{7}\).
\(= \dfrac{588}{7} = 84\).
Hence, their LCM is 84.
Find the LCM of the numbers 780, 2080 and 2600.
Six bells begin to toll together and toll, respectively, at intervals of 3, 4, 6, 7, 8 and 12 seconds. After how many seconds, will they toll together again?
A and B are two prime numbers such that A > B and their LCM is 209. The value of A 2 - B is:
Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.
Calculate the HCF of \(\frac{12}{5}\) , \(\frac{14}{15}\) and \(\frac{16}{17}\) .
Three numbers are in the proportion of 3 : 8 : 15 and their LCM is 8280. What is their HCF?