In a test, B got 50 marks while A got 75 marks, out of 110 maximum marks. What percentage of A's marks was B's marks? (Round off your answer to two decimal places.)
66.67%
We need to express B's marks as a percentage of A's marks, so the base is A's marks (75), not the maximum marks.
Required percentage \(= \dfrac{\text{B's marks}}{\text{A's marks}} \times 100 = \dfrac{50}{75} \times 100\).
Simplifying: \(\dfrac{50}{75} = \dfrac{2}{3}\), so the percentage \(= \dfrac{2}{3} \times 100 = 66.666\ldots\%\).
Rounded to two decimal places, this is 66.67%.
Hence, B's marks were 66.67% of A's marks.
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