A MOSFET differs from the JFET because 1. of the characteristics 2. the MOSFET has two gates 3. the JFET has p-n junctions 4. of the physical reduced size
1 & 3
Statement 3 names the fundamental structural difference and statement 1 names its visible consequence — so the answer is 1 & 3, option 2.
Statement 3 — the physics. A JFET's gate is a reverse-biased p-n junction, and its depletion region squeezes the channel. A MOSFET's gate is a metal or polysilicon plate separated from the channel by an insulating oxide; there is no junction anywhere near it. That one difference produces every other:
| JFET | MOSFET | |
|---|---|---|
| Gate | p-n junction | Insulated by SiO2 |
| Gate current | Small leakage, nA | Essentially zero, pA |
| Input impedance | ~109 Ω | ~1014 Ω |
| Gate polarity | Reverse bias only | Either polarity |
| Modes | Depletion only | Depletion and enhancement |
Statement 1 — the characteristics. This follows directly. Because the JFET's gate junction must stay reverse biased, forward bias would make it conduct, so the gate can only ever reduce the channel: the JFET is a depletion-mode device with the channel present at \(V_{GS}=0\). The MOSFET's oxide permits gate voltage of either sign, so an enhancement device is possible, one with no channel at all until the gate creates an inversion layer:
\(I_{D}=K\left(V_{GS}-V_{T}\right)^{2}\qquad\text{for}\ V_{GS}\gt V_{T}\)
Its transfer curve sits entirely in the positive \(V_{GS}\) region, while the JFET's lies entirely in the negative — visibly different characteristics.
Why statement 2 is false. A MOSFET has one gate. Dual-gate MOSFETs exist and are used as mixers and AGC amplifiers, but they are a special type, not what distinguishes MOSFETs from JFETs. The four-terminal MOSFET's extra terminal is the substrate or body, not a second gate.
Why statement 4 is false as a distinguishing reason. MOSFETs are indeed the smaller devices — which is why integrated circuits are built from them and not from JFETs — but small size is a consequence of the fabrication process, not the reason the two device types differ in operation. The question asks what makes a MOSFET a different device.
Hence, statements 1 and 3 are correct.
Match the following :
| List - I | List - II (figure in the original question) |
| (a) n-channel Enhancement (Normally off) | (i) ![]() |
| (b) p-channel Depletion MOSFET (Normally on) | (ii) ![]() |
| (c) n-channel FET | (iii) ![]() |
| (d) p-channel Enhancement MOSFET | (iv) ![]() |
Codes :
Match the following :
| List - I | List - II (figure in the original question) |
| (a) n-channel Enhancement (Normally off) | (i) ![]() |
| (b) p-channel Depletion MOSFET (Normally on) | (ii) ![]() |
| (c) n-channel FET | (iii) ![]() |
| (d) p-channel Enhancement MOSFET | (iv) ![]() |
Codes :
The pull up to pull down ratio for an n mos inverter driven by another n mos inverter can be evaluated from:
(A) Vi nv = V t − \(\rm\frac{V_{t d}}{\sqrt{Zpu/Zpd}}\)
(B) V inv = \(\rm\frac{−V_{t d}}{\sqrt{Zpu/Zpd}}\)
(C) \(\rm\frac{W_{pd}}{L_{pd}}\) (V inv − V t) 2= \(\rm\frac{W_{p u}}{L_{p u}}\) (−V td )2
(D) \(\rm\frac{W_{p d}}{L_{p d}}\) (V inv − V t ) = \(\rm\frac{W_{p u}}{L_{pu}}\) (−V td )2
Choose the correct answer from the options given below:
Match List I with List II:
| List I | List II | ||
| (A) | JFET | (I) | Two dimensional electron gas |
| (B) | MOSFET | (II) | Negative resistance device |
| (C) | Tunnel diode | (III) | Enhancement mode |
| (D) | HEMT | (IV) | Voltage controlled resistor |
Choose the correct answer from the options given below:
Which of the following is NOT a minority carrier semiconductor device ?
The metal gate that is insulated from the channel is also referred to as: