A man is walking at 4 km/hr. A 180 m long train crosses him in 12 seconds while coming from the opposite direction. What is the speed of the train (in km/hr)?
50
Since the train and the man are moving in opposite directions, their relative speed is the sum of their individual speeds.
The train crosses the man in 12 seconds, covering a distance equal to the train's length, 180 m.
Relative speed \(= \frac{180}{12} = 15\) m/s.
Convert to km/hr: \(15 \times \frac{18}{5} = 54\) km/hr.
This relative speed equals (speed of train + speed of man): \(v_{\text{train}} + 4 = 54\).
Therefore, \(v_{\text{train}} = 54 - 4 = 50\) km/hr.
Hence, the speed of the train is 50 km/hr.
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