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Question

A girl starts from her school gate and walks 10 m East, then 4 m South, then 8 m West. She then walks 2 m North, turns right and walks 6 m. After that, she turns left and walks 2 m, and finally turns left again and walks 6 m. Where is she from the school gate?

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
2 m East

Step-by-Step Solution: Girl's Walk from School

This problem requires us to determine the final position of a girl relative to her starting point (the school gate) after a series of movements. We can track her position using a coordinate system, where the school gate is the origin $(0, 0)$. We'll define East as the positive x-direction, West as the negative x-direction, North as the positive y-direction, and South as the negative y-direction.

Tracking the Girl's Movements

Let's follow each step of her journey:

  • Starting Point: School Gate at coordinates $(0, 0)$.
  • 1. Walks 10 m East:
    • Movement: $+10$ m along the x-axis.
    • New Position: $(0 + 10, 0) = (10, 0)$.
  • 2. Walks 4 m South:
    • Movement: $-4$ m along the y-axis.
    • New Position: $(10, 0 - 4) = (10, -4)$.
  • 3. Walks 8 m West:
    • Movement: $-8$ m along the x-axis.
    • New Position: $(10 - 8, -4) = (2, -4)$.
  • 4. Walks 2 m North:
    • Movement: $+2$ m along the y-axis.
    • New Position: $(2, -4 + 2) = (2, -2)$.
  • 5. Turns right and walks 6 m:
    • At this point, she is facing North (from the previous step). Turning right means she now faces East.
    • Movement: $+6$ m along the x-axis.
    • New Position: $(2 + 6, -2) = (8, -2)$.
  • 6. Turns left and walks 2 m:
    • She is currently facing East. Turning left means she now faces North.
    • Movement: $+2$ m along the y-axis.
    • New Position: $(8, -2 + 2) = (8, 0)$.
  • 7. Turns left again and walks 6 m:
    • She is currently facing North. Turning left means she now faces West.
    • Movement: $-6$ m along the x-axis.
    • Final Position: $(8 - 6, 0) = (2, 0)$.

Calculating Net Displacement

Alternatively, we can sum the displacements along each axis:

  • East-West (x-axis) Displacement:
    • Movements: $+10$ m (East), $-8$ m (West), $+6$ m (East), $-6$ m (West).
    • Net x-displacement = $10 - 8 + 6 - 6 = 2$ m.
  • North-South (y-axis) Displacement:
    • Movements: $-4$ m (South), $+2$ m (North), $+2$ m (North).
    • Net y-displacement = $-4 + 2 + 2 = 0$ m.

The net displacement is $2$ m in the East direction and $0$ m in the North-South direction. The final coordinates are $(2, 0)$.

Final Position Relative to School Gate

The final position $(2, 0)$ means the girl is 2 meters from the origin along the positive x-axis. Since the positive x-axis represents East, she is 2 meters East of the school gate.

Therefore, the girl is located 2 m East from the school gate.

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Important Questions from Direction and Distance

  1. What is the direction of U with respect to P?

  2. What is the shortest distance between R and T?

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