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Question

A girl starts from her school gate and walks 10 m East, then 4 m South, then 8 m West. She then walks 2 m North, turns right and walks 6 m. After that, she turns left and walks 2 m, and finally turns left again and walks 6 m. Where is she from the school gate?

This question was previously asked in
SSC Stenographer 2025 Question Paper (06-Aug-2025) Shift 2
The correct answer is
2 m East

Step-by-Step Solution: Girl's Walk from School

This problem requires us to determine the final position of a girl relative to her starting point (the school gate) after a series of movements. We can track her position using a coordinate system, where the school gate is the origin $(0, 0)$. We'll define East as the positive x-direction, West as the negative x-direction, North as the positive y-direction, and South as the negative y-direction.

Tracking the Girl's Movements

Let's follow each step of her journey:

  • Starting Point: School Gate at coordinates $(0, 0)$.
  • 1. Walks 10 m East:
    • Movement: $+10$ m along the x-axis.
    • New Position: $(0 + 10, 0) = (10, 0)$.
  • 2. Walks 4 m South:
    • Movement: $-4$ m along the y-axis.
    • New Position: $(10, 0 - 4) = (10, -4)$.
  • 3. Walks 8 m West:
    • Movement: $-8$ m along the x-axis.
    • New Position: $(10 - 8, -4) = (2, -4)$.
  • 4. Walks 2 m North:
    • Movement: $+2$ m along the y-axis.
    • New Position: $(2, -4 + 2) = (2, -2)$.
  • 5. Turns right and walks 6 m:
    • At this point, she is facing North (from the previous step). Turning right means she now faces East.
    • Movement: $+6$ m along the x-axis.
    • New Position: $(2 + 6, -2) = (8, -2)$.
  • 6. Turns left and walks 2 m:
    • She is currently facing East. Turning left means she now faces North.
    • Movement: $+2$ m along the y-axis.
    • New Position: $(8, -2 + 2) = (8, 0)$.
  • 7. Turns left again and walks 6 m:
    • She is currently facing North. Turning left means she now faces West.
    • Movement: $-6$ m along the x-axis.
    • Final Position: $(8 - 6, 0) = (2, 0)$.

Calculating Net Displacement

Alternatively, we can sum the displacements along each axis:

  • East-West (x-axis) Displacement:
    • Movements: $+10$ m (East), $-8$ m (West), $+6$ m (East), $-6$ m (West).
    • Net x-displacement = $10 - 8 + 6 - 6 = 2$ m.
  • North-South (y-axis) Displacement:
    • Movements: $-4$ m (South), $+2$ m (North), $+2$ m (North).
    • Net y-displacement = $-4 + 2 + 2 = 0$ m.

The net displacement is $2$ m in the East direction and $0$ m in the North-South direction. The final coordinates are $(2, 0)$.

Final Position Relative to School Gate

The final position $(2, 0)$ means the girl is 2 meters from the origin along the positive x-axis. Since the positive x-axis represents East, she is 2 meters East of the school gate.

Therefore, the girl is located 2 m East from the school gate.

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Similar Questions

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  2. Kedar starts form his house and travel s 25 km towards the south by bicycle and reaches the bus stand. Then he takes a left turn and travels 15 km., take takes a left turn again and travels 25 km more. How far is he form his original position?

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Important Questions from Direction and Distance

  1. What is the direction of U with respect to P?

  2. What is the shortest distance between R and T?

  3. If a person walks 3m towards the North from point V, takes a right turn and walks for another 15m, which of the following points would he reach?

  4. In which direction is Amit facing at point F?

  5. What is the distance between the starting point and the end point?

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