A drawing specifies a hole with 12.00 +0.02/-0.00 mm. What is the minimum permissible diameter of the hole?
12.00 mm
In the limits-and-fits system a size is written as a basic (nominal) size followed by an upper and a lower deviation, and the actual finished dimension is allowed to lie anywhere between the two limits these deviations define.
Here the basic size is 12.00 mm, the upper deviation is +0.02 mm and the lower deviation is -0.00 mm.
The maximum permissible size is basic size plus upper deviation, \(12.00+0.02=12.02\) mm, which sets the largest the hole may be.
The minimum permissible size is basic size plus lower deviation, \(12.00+0.00=12.00\) mm.
Because the lower deviation is exactly zero, the smallest the hole may legitimately be is the basic size itself, so 12.00 mm is the low limit.
The value 12.02 mm is actually the maximum, not the minimum; 12.01 mm lies inside the tolerance band but is not a limit; and 12.20 mm misreads the decimal and lies far outside the +0.02 upper limit.
Hence, the answer is 12.00 mm.
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Important Questions from Limits and Fits
The following limits are specified in a limit system, to give a clearance fit between a hole and a shaft:
\(Hole = 25_{ - 0.01}^{ + 0.02}\;mm\;and\;shaft = 25_{ - 0.02}^{ - 0.004}\;mm\)
Determine tolerance on a shaft.
When tolerance is given on one side of the basic dimension, it is called:
In a hole and shaft tolerance system, the small letter indicates fundamental deviation of________
Which of the following fit is produced with the shaft dia 25.025 and bore dia of 24.994?
In mass production, parts made to definite limit of error is called as ______
