A and B can complete a task in 12 days together. A is 25% more efficient than B. What percentage of the work is done by A alone?
55.56%
Since A is 25% more efficient than B, the ratio of their efficiencies is \(A:B = 125:100 = 5:4\).
Let A's daily work rate be \(5k\) and B's be \(4k\), so their combined rate is \(9k\) per day.
Together they complete the work in 12 days, so \(9k \times 12 = 1\) (total work), giving \(k = \frac{1}{108}\).
The percentage of work done by A alone (out of the combined work) is \(\frac{5k}{9k} \times 100 = \frac{5}{9} \times 100\).
Calculating, \(\frac{5}{9} \times 100 = 55.56\%\).
Hence, the answer is 55.56%.
Similar Questions
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Important Questions from Work Efficiency
A and B together can complete a certain work in 20 days whereas B and C together can complete it in 24 days. If A is twice as good a workman as C, then in what time will B alone do 40% of the same work?
14 men can complete a work in 15 days. If 21 men are employed, then in how many days will they complete the same work?
A can do a certain work in 15 days, while B can do the same work in 21 days. If they work together, then in how many days will the same work be completed?
To do a certain work, A and B work on alternate days with B beginning the work on the first day. A alone can complete the same work in 24 days. If the work gets completed in \(11 \frac{1}{3}\) days, then B alone can complete \(\rm \frac{7}{9}^{th}\) part of the original work in:
Two men and 7 women can complete a work in 28 days whereas 6 men and 16 women can do the same work in 11 days. In how many days can 7 men complete the same work?
