This problem involves calculating the number of printers required based on the rate of printing, the number of pages, and the time available. We can solve this using a proportional reasoning approach.
The relationship between the number of printers (P), the time spent (T), and the work done (W) can be expressed as:
\( \frac{P_1 \times T_1}{W_1} = \frac{P_2 \times T_2}{W_2} \)
Where:
Substitute the known values into the formula:
\( \frac{5 \times 6}{9000} = \frac{P_2 \times 8}{28800} \)
Calculate the left side:
\( \frac{30}{9000} = \frac{1}{300} \)
The equation becomes:
\( \frac{1}{300} = \frac{P_2 \times 8}{28800} \)
Rearrange the equation to isolate \(P_2\):
\( P_2 = \frac{1}{300} \times \frac{28800}{8} \)
\( P_2 = \frac{1}{300} \times 3600 \)
\( P_2 = \frac{3600}{300} \)
\( P_2 = 12 \)
Therefore, 12 printers are needed to print 28,800 pages in 8 hours.
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P works thrice as fast as Q, whereas P and Q together can work four times as fast as R. If P, Q and R together work on a job, in what ratio should they share the earnings?
There are three pillars X, Y and Z of different heights. Three spiders A, B and C start to climb on these pillars simultaneously. In one chance, A climbs on X by 6 cm but slips down 1 cm. B climbs on Y by 7 cm but slips down 3 cm. C climbs on Z by 6.5 cm but slips down 2 cm. If each of them requires 40 chances to reach the top of the pillars, what is the height of the shortest pillar?
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Ram and Shyam work on a job together for four days and complete 60% of it. Ram takes leave then and Shyam works for eight more days to complete the job. How long would Ram take to complete the entire job alone?