If 6 men and 8 boys can do a piece of work in 10 days, while 26 men and 48 boys can do the same work in 2 days, then the time taken by 20 men to do the same piece of work is:
5 days
The correct answer is Option 2 i.e. 5 days.
Let the work done by one man in one day be M, and by one boy in one day be B
⇒ (6M + 8B) × 10 = (26M + 48B) × 2 (6M + 8B) × 5 = (26M + 48B)
⇒ 30M + 40B = 26M + 48B
⇒ 4M = 8B
⇒ M/B = 2/1
Total work = (6M + 8B) × 10
⇒ (6 × 2 + 8 × 1) × 10 = 200 units
Time = 200/(20 × 2) = 200/40 = 5 days
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