A and B can together complete a piece of work in 5 days. They worked together for 4 days, and then B left. After another 2 days, A completed the remaining work. In how many days can A complete the entire work alone?
10
The correct answer is Option 3 i.e. 10.
Let A alone complete the work in x days
A's 1 day work = \(1\over x\)
1 day work of A and B = \(1\over 5\)
Work done in first 4 days = 4 × \(1\over 5\) = \(4\over 5\)
Remaining work = 1 - \(4\over 5\) = \(1\over 5\)
A's 1 day work = \(1\over 5\) ÷ 2 = \(1\over 10\)
⇒ x = 10 days
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