15 small rods, each of length \(23\frac{2}{7}\) m are joined to make a big rod. What then is the length of the big rod?
This problem asks us to find the total length of a big rod created by joining several smaller rods end-to-end. We are given the number of small rods and the length of each individual small rod. To find the total length, we need to multiply the length of one small rod by the total number of small rods.
Let's break down the given information:
The length of each small rod is given as a mixed number. To perform multiplication easily, it's best to convert this mixed number into an improper fraction.
A mixed number like \(a\frac{b}{c}\) can be converted to an improper fraction using the formula \(\frac{(a \times c) + b}{c}\).
For the length \(23\frac{2}{7}\) m:
Here, \(a = 23\), \(b = 2\), and \(c = 7\).
Improper fraction = \(\frac{(23 \times 7) + 2}{7}\)
Calculating the numerator:
\(23 \times 7 = 161\)
\(161 + 2 = 163\)
So, the improper fraction is \(\frac{163}{7}\).
The length of each small rod is \(\frac{163}{7}\) m.
The total length of the big rod is the product of the number of small rods and the length of one small rod.
Total Length = Number of rods \(\times\) Length of each rod
Total Length = \(15 \times \frac{163}{7}\)
To multiply a whole number by a fraction, we multiply the whole number by the numerator of the fraction and keep the denominator the same.
Total Length = \(\frac{15 \times 163}{7}\)
Let's calculate the product \(15 \times 163\):
\(163 \times 15 = 2445\)
So, the total length in meters is \(\frac{2445}{7}\).
The total length is \(\frac{2445}{7}\) m. To express this as a mixed number, we need to divide the numerator (2445) by the denominator (7).
We perform long division:
\(2445 \div 7\)
The quotient of the division is 349, and the remainder is 2. The denominator remains 7.
So, the improper fraction \(\frac{2445}{7}\) is equal to the mixed number \(349\frac{2}{7}\).
The total length of the big rod is \(349\frac{2}{7}\) m.
By joining 15 small rods, each \(23\frac{2}{7}\) m long, the total length of the resulting big rod is \(349\frac{2}{7}\) m.
| Step | Description | Calculation |
|---|---|---|
| 1 | Convert mixed number length to improper fraction | \(23\frac{2}{7} = \frac{(23 \times 7) + 2}{7} = \frac{163}{7}\) m |
| 2 | Multiply length by number of rods | Total Length = \(15 \times \frac{163}{7}\) m |
| 3 | Perform the multiplication | Total Length = \(\frac{15 \times 163}{7} = \frac{2445}{7}\) m |
| 4 | Convert improper fraction back to mixed number | \(\frac{2445}{7} = 349\) with remainder \(2\). So, \(349\frac{2}{7}\) m |
Understanding how to work with fractions, especially converting between mixed numbers and improper fractions, and performing operations like multiplication, is crucial for solving many mathematical problems.
This problem is a good example of applying fraction arithmetic to solve a practical length calculation question.
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