This problem involves calculating the time taken by a boy to complete a work, given combined work rates and individual work rates.
We are given that one man alone can complete the work in 100 days.
The work rate of one man (\(M\)) is the reciprocal of the time taken:
\( M = \frac{1 \text{ work}}{100 \text{ days}} = \frac{1}{100} \text{ work/day} \)
10 men and 15 boys together complete the work in 6 days.
This means their combined work rate is:
\( (10 \times M) + (15 \times B) = \frac{1 \text{ work}}{6 \text{ days}} = \frac{1}{6} \text{ work/day} \)
Where \(B\) is the work rate of one boy.
Substitute the known work rate of a man (\(M = \frac{1}{100}\)) into the combined work rate equation:
\( \left(10 \times \frac{1}{100}\right) + (15 \times B) = \frac{1}{6} \)
Simplify the term for 10 men:
\( \frac{10}{100} + 15B = \frac{1}{6} \)
\( \frac{1}{10} + 15B = \frac{1}{6} \)
Now, isolate \(15B\):
\( 15B = \frac{1}{6} - \frac{1}{10} \)
To subtract the fractions, find a common denominator (which is 30):
\( 15B = \frac{5}{30} - \frac{3}{30} \)
\( 15B = \frac{2}{30} = \frac{1}{15} \text{ work/day} \)
Now, find the work rate of a single boy (\(B\)):
\( B = \frac{1}{15 \times 15} = \frac{1}{225} \text{ work/day} \)
The time taken by one boy to complete the work is the reciprocal of his work rate:
\( \text{Time for 1 boy} = \frac{1}{B} = \frac{1}{1/225} \)
\( \text{Time for 1 boy} = 225 \text{ days} \)
Therefore, a boy alone will take 225 days to complete the same work.
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