(0.1 × 0.1 × 0.1 + 0.04 × 0.04 × 0.04) ÷ (0.2 × 0.2 × 0.2 + 0.08 × 0.08 × 0.08) = ______.
0.125
Let's solve the given mathematical expression step by step. The expression is:
\((0.1 \times 0.1 \times 0.1 + 0.04 \times 0.04 \times 0.04) \div (0.2 \times 0.2 \times 0.2 + 0.08 \times 0.08 \times 0.08)\)
We can rewrite the terms using exponents:
\((0.1^3 + 0.04^3) \div (0.2^3 + 0.08^3)\)
Let's look at the terms in the denominator and compare them to the terms in the numerator:
Now substitute these into the denominator:
\((2 \times 0.1)^3 + (2 \times 0.04)^3\)
Using the exponent rule \((ab)^n = a^n b^n\), we can write:
\(2^3 \times 0.1^3 + 2^3 \times 0.04^3\)
We can factor out \(2^3\) from both terms in the denominator:
\(2^3 (0.1^3 + 0.04^3)\)
Since \(2^3 = 2 \times 2 \times 2 = 8\), the denominator is:
\(8 (0.1^3 + 0.04^3)\)
Now substitute this back into the original expression:
\(\frac{0.1^3 + 0.04^3}{8 (0.1^3 + 0.04^3)}\)
We can see that the term \((0.1^3 + 0.04^3)\) appears in both the numerator and the denominator. As \(0.1^3 = 0.001\) and \(0.04^3 = 0.000064\), their sum is \(0.001064\), which is not zero. Therefore, we can cancel out this common term:
\(\frac{\cancel{(0.1^3 + 0.04^3)}}{8 \cancel{(0.1^3 + 0.04^3)}}\)
This simplifies the expression to:
\(\frac{1}{8}\)
Finally, convert the fraction \(\frac{1}{8}\) to a decimal:
\(1 \div 8 = 0.125\)
So, the value of the expression is 0.125.
| Step | Calculation | Result |
|---|---|---|
| Numerator terms | \(0.1^3\) | \(0.001\) |
| Numerator terms | \(0.04^3\) | \(0.000064\) |
| Denominator term relationship | \(0.2 = 2 \times 0.1\) | - |
| Denominator term relationship | \(0.08 = 2 \times 0.04\) | - |
| Denominator using relationship | \((2 \times 0.1)^3 + (2 \times 0.04)^3\) | \(2^3(0.1^3 + 0.04^3)\) |
| Simplify fraction | \(\frac{0.1^3 + 0.04^3}{8 (0.1^3 + 0.04^3)}\) | \(\frac{1}{8}\) |
| Convert to decimal | \(\frac{1}{8}\) | \(0.125\) |
This problem utilizes basic arithmetic operations with decimals and properties of exponents. Understanding these concepts is crucial for solving such expressions.
Breaking down complex expressions into simpler parts and identifying relationships between terms can make solving them much easier.
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