If a + 1/a = 3, then a 3+ 1/a 3= ?
18
This problem requires us to find the value of an algebraic expression given another related expression. We are given the value of \(a + \frac{1}{a}\) and asked to find the value of \(a^3 + \frac{1}{a^3}\).
We are given:
We need to find the value of \(a^3 + \frac{1}{a^3}\).
To solve this, we can use the algebraic identity for the cube of a sum: \((x+y)^3 = x^3 + y^3 + 3xy(x+y)\).
Let's apply this identity by setting \(x = a\) and \(y = \frac{1}{a}\). So, we have:
\(\left(a + \frac{1}{a}\right)^3 = a^3 + \left(\frac{1}{a}\right)^3 + 3 \cdot a \cdot \frac{1}{a} \cdot \left(a + \frac{1}{a}\right)\)
Let's simplify the expression:
\(\left(a + \frac{1}{a}\right)^3 = a^3 + \frac{1}{a^3} + 3 \cdot 1 \cdot \left(a + \frac{1}{a}\right)\)
\(\left(a + \frac{1}{a}\right)^3 = a^3 + \frac{1}{a^3} + 3\left(a + \frac{1}{a}\right)\)
We know that \(a + \frac{1}{a} = 3\). Let's substitute this value into the equation we derived:
\((3)^3 = a^3 + \frac{1}{a^3} + 3(3)\)
Now, calculate the values:
\(27 = a^3 + \frac{1}{a^3} + 9\)
To find the value of \(a^3 + \frac{1}{a^3}\), we need to isolate it. Subtract 9 from both sides of the equation:
\(27 - 9 = a^3 + \frac{1}{a^3}\)
\(18 = a^3 + \frac{1}{a^3}\)
The value of \(a^3 + \frac{1}{a^3}\) is 18.
| Concept | Description | Relevant Formula |
|---|---|---|
| Algebraic Identity | An equation that is true for all possible values of the variables. | \((x+y)^3 = x^3 + y^3 + 3xy(x+y)\) |
| Cubing a Sum | Raising a binomial expression (sum of two terms) to the power of 3. | \((x+y)^3\) |
Understanding algebraic identities is crucial for solving many algebra problems. Here are a few other common identities:
These identities help simplify expressions and solve equations more efficiently, especially in problems involving powers of variables like the given question where we found the value of \(a^3 + \frac{1}{a^3}\) using the identity for \((a + \frac{1}{a})^3\).
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