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Question

If a + 1/a = 3, then a 3+ 1/a 3= ?

This question was previously asked in
RRB ALP 2018 CBT 2 Fitter Question Paper (21-Jan-2019) (Shift 3)
The correct answer is

18

Finding the Value of a<sup>3</sup> + 1/a<sup>3</sup>

This problem requires us to find the value of an algebraic expression given another related expression. We are given the value of \(a + \frac{1}{a}\) and asked to find the value of \(a^3 + \frac{1}{a^3}\).

We are given:

  • \(a + \frac{1}{a} = 3\)

We need to find the value of \(a^3 + \frac{1}{a^3}\).

Using Algebraic Identities to Solve

To solve this, we can use the algebraic identity for the cube of a sum: \((x+y)^3 = x^3 + y^3 + 3xy(x+y)\).

Let's apply this identity by setting \(x = a\) and \(y = \frac{1}{a}\). So, we have:

\(\left(a + \frac{1}{a}\right)^3 = a^3 + \left(\frac{1}{a}\right)^3 + 3 \cdot a \cdot \frac{1}{a} \cdot \left(a + \frac{1}{a}\right)\)

Let's simplify the expression:

\(\left(a + \frac{1}{a}\right)^3 = a^3 + \frac{1}{a^3} + 3 \cdot 1 \cdot \left(a + \frac{1}{a}\right)\)

\(\left(a + \frac{1}{a}\right)^3 = a^3 + \frac{1}{a^3} + 3\left(a + \frac{1}{a}\right)\)

Calculation Steps

We know that \(a + \frac{1}{a} = 3\). Let's substitute this value into the equation we derived:

\((3)^3 = a^3 + \frac{1}{a^3} + 3(3)\)

Now, calculate the values:

\(27 = a^3 + \frac{1}{a^3} + 9\)

To find the value of \(a^3 + \frac{1}{a^3}\), we need to isolate it. Subtract 9 from both sides of the equation:

\(27 - 9 = a^3 + \frac{1}{a^3}\)

\(18 = a^3 + \frac{1}{a^3}\)

Conclusion

The value of \(a^3 + \frac{1}{a^3}\) is 18.

Revision Table: Key Concepts

Concept Description Relevant Formula
Algebraic Identity An equation that is true for all possible values of the variables. \((x+y)^3 = x^3 + y^3 + 3xy(x+y)\)
Cubing a Sum Raising a binomial expression (sum of two terms) to the power of 3. \((x+y)^3\)

Additional Information: Related Algebraic Identities

Understanding algebraic identities is crucial for solving many algebra problems. Here are a few other common identities:

  • Square of a sum: \((x+y)^2 = x^2 + y^2 + 2xy\)
  • Square of a difference: \((x-y)^2 = x^2 + y^2 - 2xy\)
  • Cube of a difference: \((x-y)^3 = x^3 - y^3 - 3xy(x-y)\)
  • Difference of squares: \(x^2 - y^2 = (x-y)(x+y)\)
  • Sum of cubes: \(x^3 + y^3 = (x+y)(x^2 - xy + y^2)\)
  • Difference of cubes: \(x^3 - y^3 = (x-y)(x^2 + xy + y^2)\)

These identities help simplify expressions and solve equations more efficiently, especially in problems involving powers of variables like the given question where we found the value of \(a^3 + \frac{1}{a^3}\) using the identity for \((a + \frac{1}{a})^3\).

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Important Questions from Identities

  1. If \(2x + { {1} \over 3x}= 5, x ≠ 0\) , then what is the value of  \(27x^3+{{1} \over 8x^3}\) ?

  2. If x 2 + 4y 2 = 40, xy = 6 and x > 2y then the value of x - 2y is:

  3. \(\dfrac{(0.73)^3+(0.31)^3}{(0.73)^2-0.73\times0.31+(0.31)^2}\)
  4. \(\dfrac{(5.17-2.19)^2-(5.17+2.19)^2}{11.3223}\)
  5. If a(a + b + c) 2= 1792; b(a + b + c) 2= 1536; c(a + b + c) 2= 768 then what will be the value of a?

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