Which two signs should be interchanged to make the given equation correct? 32 + 24 × 4 ÷ 16 – 64 = 90
+ and –
The question asks us to find which pair of mathematical signs, when interchanged in the given equation, makes the equation correct. The original equation is:
\(32 + 24 \times 4 \div 16 – 64 = 90\)
We need to test each given option by interchanging the specified signs and then evaluating the modified equation using the BODMAS (or PEMDAS) rule to see if it equals 90.
Remember the order of operations according to the BODMAS rule:
If we interchange '+' and '×', the equation becomes:
\(32 \times 24 + 4 \div 16 – 64\)
Let's evaluate this:
\(704.25 \neq 90\). So, this option is incorrect.
If we interchange '÷' and '+', the equation becomes:
\(32 \div 24 \times 4 + 16 – 64\)
Let's evaluate this:
\(\frac{-128}{3} \neq 90\). So, this option is incorrect.
If we interchange '÷' and '×', the equation becomes:
\(32 + 24 \div 4 \times 16 – 64\)
Let's evaluate this:
\(64 \neq 90\). So, this option is incorrect.
If we interchange '+' and '–', the equation becomes:
\(32 – 24 \times 4 \div 16 + 64\)
Let's evaluate this:
\(90 = 90\). This makes the equation correct.
Interchanging the signs '+' and '–' makes the given equation correct. Therefore, Option 4 is the correct answer.
| Signs Interchanged | New Equation | Result | Correct? |
|---|---|---|---|
| + and × | \(32 \times 24 + 4 \div 16 – 64\) | \(704.25\) | No |
| ÷ and + | \(32 \div 24 \times 4 + 16 – 64\) | \(\frac{-128}{3}\) | No |
| ÷ and × | \(32 + 24 \div 4 \times 16 – 64\) | \(64\) | No |
| + and – | \(32 – 24 \times 4 \div 16 + 64\) | \(90\) | Yes |
Solving problems that involve interchanging signs or numbers in an equation requires careful application of the order of operations (BODMAS/PEMDAS). Here are some tips:
Read the given statements and conclusions carefully. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. You have to decide which conclusion/s logically follow/s from the given statements.
Statements:
All beaches are sand.
Some deserts are sand.
All mountains are rocky.
Conclusions:
(I) At least some beaches are desert.
(II) At least some sands are rocky.
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