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Question

Select the correct combination of mathematical signs to sequentially replace the @ signs and to balance the given equation.

[{(14 @ 6) @ (2 @ 3)} @ (1 @ 7)] @ 2 @ 4

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

−, +, ×, ÷, ×, ×, =

Balancing Mathematical Equations by Substituting Signs

The question asks us to find the correct combination of mathematical signs to replace the '@' symbols in the given equation so that it balances. We are provided with a complex expression involving nested brackets and several '@' placeholders.

The equation structure is given as:

\({[\{(14 @ 6) @ (2 @ 3)\} @ (1 @ 7)] @ 2 @ 4}\)

Let's carefully identify the positions of the '@' symbols within the structure. There are a total of seven '@' symbols:

  1. Between 14 and 6
  2. Between the result of \((14 @ 6)\) and the result of \((2 @ 3)\)
  3. Between 2 and 3
  4. Between the result of \(\{(14 @ 6) @ (2 @ 3)\}\) and the result of \((1 @ 7)\)
  5. Between 1 and 7
  6. Between the result of the entire expression within the square brackets \([\dots]\) and the number 2
  7. Between 2 and 4

The options provided contain a sequence of seven mathematical signs. The last sign in each option is '=', which indicates that the last '@' symbol represents the equality sign, and the number '4' is on the right side of the equation. Thus, the equation we need to balance is:

\({[\{(14 @ 6) @ (2 @ 3)\} @ (1 @ 7)] @ 2 = 4}\)

We need to test the given options by substituting the signs sequentially into the positions of the '@' symbols. Let's use the signs from one of the options and evaluate the left side of the equation to see if it equals 4.

Let's consider the sequence of signs: \(\minus, +, \times, \div, \times, \times, =\). Substituting these signs into the equation gives:

\({[\{(14 - 6) + (2 \times 3)\} \div (1 \times 7)] \times 2 = 4}\)

Step-by-Step Evaluation Using BODMAS/PEMDAS

We will evaluate the left side of this equation following the standard order of operations (Brackets/Parentheses, Orders/Exponents, Division & Multiplication, Addition & Subtraction):

  1. Evaluate the expressions inside the innermost parentheses first:
    • Calculate \((14 - 6)\): \(14 - 6 = 8\)
    • Calculate \((2 \times 3)\): \(2 \times 3 = 6\)
    • Calculate \((1 \times 7)\): \(1 \times 7 = 7\)
  2. Substitute these calculated values back into the equation:

    \({[\{(8) + (6)\} \div (7)] \times 2 = 4}\)

  3. Next, evaluate the expression within the curly braces \(\{\}\):
    • Calculate \(\{(8) + (6)\}\): \(8 + 6 = 14\)
  4. Substitute this value back:

    \({[\{14\} \div (7)] \times 2 = 4}\)

  5. Now, evaluate the expression within the square brackets \(\lbrack\rbrack\):
    • Calculate \([\text{14} \div \text{7}]\): \(14 \div 7 = 2\)
  6. Substitute this result back into the equation:

    \({2 \times 2 = 4}\)

  7. Finally, perform the multiplication on the left side:
    • Calculate \({2 \times 2}\): \(2 \times 2 = 4\)

After performing all operations on the left side, we get the value 4. The equation becomes:

\({4 = 4}\)

Since the left side of the equation is equal to the right side, the equation is balanced with the sequence of signs \(\minus, +, \times, \div, \times, \times, =\).

The correspondence between the '@' positions and the signs used is:

@ Position Mathematical Sign
1st @ (between 14 and 6) \(\minus\)
2nd @ (between (14-6) and (2x3)) \(+\)
3rd @ (between 2 and 3) \(\times\)
4th @ (between {(14-6)+(2x3)} and (1x7)) \(\div\)
5th @ (between 1 and 7) \(\times\)
6th @ (between [...] and 2) \(\times\)
7th @ (between 2 and 4) \(=\)

This sequence of signs successfully balances the given equation, making the statement true.

Revision Table: Key Concepts for Equation Balancing

Concept Relevance to Balancing Equations
Substituting Signs The core task is replacing placeholders (@) with operators (+, -, ×, ÷) and the equality sign (=).
Order of Operations (BODMAS/PEMDAS) Crucially important for evaluating the mathematical expression correctly after substitution. Determines the sequence of calculations (Brackets/Parentheses first, then Orders/Exponents, then Division/Multiplication from left to right, then Addition/Subtraction from left to right).
Evaluating Expressions Calculating the numerical value of the expression on the left side of the equation.
Equality (=) The symbol that signifies that the value on the left side is the same as the value on the right side. The goal is to achieve a true equality.

Additional Information: Importance of Brackets in Expressions

Brackets, parentheses, and braces are used in mathematical expressions to group terms and dictate the order in which operations should be performed, overriding the default BODMAS/PEMDAS order if necessary. Operations within the innermost brackets are always performed first.

  • Parentheses (): Used for the innermost grouping.
  • Curly Braces {}: Used for the next level of grouping outside parentheses.
  • Square Brackets []: Used for the outermost level of grouping in complex expressions.

In the given problem, the structure \({[\{(...)\}] \dots}\) clearly shows the nesting levels, guiding the evaluation process from the inside out. Ignoring or misinterpreting the brackets would lead to incorrect results when evaluating the expression and attempting to balance the equation.

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Important Questions from Logical Puzzle

  1. Seven persons P, Q, R, S, T, U and V like different watches namely W1, W2, W3, W4, W5, W6 and W7 (not necessarily in the same order). P and R do not like odd numbered watch. T likes W5. U does not like W2 or W3 or W6 or W7. P likes prime numbered watch. Q likes W4. S likes W2 or W7. Which of the following statement(s) is/are correct ?

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  2. If ‘+’ means ‘×’, ‘×’ means ‘÷’, ‘÷’ means ‘–’ and ‘–’ means ‘+’, then

    16 + 18 × 3 ÷ 6 = ?

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  4. In a certain code language, ‘LETTER’ is written as ‘ZLZYIO’. What is the code for ‘ACTION’ in that code language?

  5. If A denotes ‘+’, B denotes ‘×’, C denotes ‘-’, and D denotes ‘÷’, then what will come in place of ‘?’ in the following equation?

    34 A 15 B 3 C 11 B 2 A (51 D 17) = ?

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