Which option is incorrect?
mean sum of square of total = mean sum of square of treatment + mean sum of square of error
The question asks us to identify the incorrect statement among the given options related to ANOVA (Analysis of Variance). ANOVA is a statistical technique used to compare means of three or more groups. It partitions the total variability observed in a dataset into different components.
In a one-way ANOVA, the total variation in the data is split into two parts:
This partitioning applies to both the Sum of Squares (SS) and the Degrees of Freedom (df).
The total sum of squares (\(SS_{Total}\)) represents the total variation in the data. It is the sum of the sum of squares between groups (\(SS_{Between}\) or \(SS_{Treatment}\)) and the sum of squares within groups (\(SS_{Within}\) or \(SS_{Error}\)).
\(SS_{Total} = SS_{Between} + SS_{Within}\)
or
\(SS_{Total} = SS_{Treatment} + SS_{Error}\)
Similarly, the total degrees of freedom (\(df_{Total}\)) is partitioned into the degrees of freedom between groups (\(df_{Between}\) or \(df_{Treatment}\)) and the degrees of freedom within groups (\(df_{Within}\) or \(df_{Error}\)).
For k treatments (groups) and a total of N observations:
Check: \((k - 1) + (N - k) = N - 1\), which holds true.
The Mean Sum of Squares (MS) is calculated by dividing the Sum of Squares by its corresponding Degrees of Freedom.
Unlike the Sum of Squares and Degrees of Freedom, the Mean Sum of Squares are not additive. That is, \(MS_{Total} \neq MS_{Treatment} + MS_{Error}\).
Let's examine each option based on these principles.
Option 1: For k treatments and N observations, the degree of freedom of variation between group is k - 1
As discussed above, the degrees of freedom for variation between groups (treatment) is indeed \(k-1\). This statement is correct.
Option 2: mean sum of square of total = mean sum of square of treatment + mean sum of square of error
The Mean Sum of Squares are calculated by dividing the Sum of Squares by their respective Degrees of Freedom. While Sum of Squares and Degrees of Freedom are additive, Mean Sum of Squares are generally not additive in this manner. \(MS_{Total}\), \(MS_{Treatment}\), and \(MS_{Error}\) do not have this simple linear relationship. This statement is incorrect.
Option 3: sum of square of total = sum of square of treatment + sum of square of error
This statement reflects the fundamental additive property of Sum of Squares in ANOVA, where the total variability is decomposed into variability between groups and variability within groups. This statement is correct.
Option 4: For k treatments and N observations, the degree of freedom of variation within group is N - k
The degrees of freedom for variation within groups (error) is calculated as the total degrees of freedom minus the between-group degrees of freedom: \((N-1) - (k-1) = N-1-k+1 = N-k\). This statement is correct.
Based on the analysis, the incorrect option is the one stating that the mean sum of square of total equals the sum of the mean sum of square of treatment and mean sum of square of error.
The incorrect statement is option 2.
| Component | Sum of Squares (SS) | Degrees of Freedom (df) | Mean Sum of Squares (MS) | Relationship |
|---|---|---|---|---|
| Total | \(SS_{Total}\) | \(df_{Total} = N - 1\) | \(MS_{Total} = \frac{SS_{Total}}{df_{Total}}\) | |
| Between Groups (Treatment) | \(SS_{Treatment}\) | \(df_{Treatment} = k - 1\) | \(MS_{Treatment} = \frac{SS_{Treatment}}{df_{Treatment}}\) | |
| Within Groups (Error) | \(SS_{Error}\) | \(df_{Error} = N - k\) | \(MS_{Error} = \frac{SS_{Error}}{df_{Error}}\) | |
| Additive Property | \(SS_{Total} = SS_{Treatment} + SS_{Error}\) | \(df_{Total} = df_{Treatment} + df_{Error}\) | \(MS_{Total} \neq MS_{Treatment} + MS_{Error}\) | MS are not directly additive |
The main purpose of ANOVA is to test the hypothesis that the means of several groups are equal. The test is based on comparing the variability between the groups to the variability within the groups.
The test statistic used in ANOVA is the F-statistic, which is the ratio of the mean sum of squares between groups to the mean sum of squares within groups.
\(F = \frac{MS_{Between}}{MS_{Within}} = \frac{MS_{Treatment}}{MS_{Error}}\)
A large F-statistic indicates that the variability between groups is much larger than the variability within groups, suggesting that the group means are likely different.
Which of the following is a merit of data tabulation?
In seasonal variations, the duration of time is not more than:
If a constant is added to each observation of a data set, then which of the following measures of dispersion will change?
Which of the following is NOT true for seasonal variation?
The analysis of variance technique was developed by:
For the series 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, the minimum possible value of \(\rm \Sigma_{i=1}^n(x_i-A)^2\) can be attained at:
Suppose that a sample of 100 independent draws from a normal distribution having unknown mean μ and known variance σ2 = 1 is observed. If the sample mean is 5, then the 95% confidence interval for μ is:
Consider the following ANOVA table.
| Source of variation | Degrees of freedom | The sum of Squares (SS) | Mean SS | F Ratio |
| Treatments | a | b | c | 5 |
| Error | 12 | d | 20 | |
| Total | 15 | 540 |
If the mean, mode and quartile deviation of a distribution is 2, 7 and 3, respectively, then Karl Pearson's coefficient of skewness is given by:
The component containing the overall upward or downward pattern of the data in an annual time series is:
Match the following:
| (a) Marginalist Revolution | (i) Samuelson |
| (b) Multiplier-Accelerator model | (ii) J. R. Hicks |
| (c) IS-LM curves | (iii) Jevous |
| (d) Real Business Cycle | (iv) Robert J. Borro |
Choose the correct option from those given below:
As per the SRS Bulletin of September 2017, the estimated death rate for Kerala is 7.6, while for Bihar it is 6. From these data which is the correct inference to draw?
Arrange the following States in descending order according to Maternal Mortality Ratio (MMR) as per the Special Bulletin of SRS, May, 2018:
(i) Assam
(ii) Bihar
(iii) Madhya Pradesh
(iv) Uttar Pradesh
Choose the correct answer from the code given below :
Which of the following statements is true for the Indian economy according to the World Bank figures for 2017?
Harrod's Growth model is given as under:
\(\begin{array}{ll} \mathrm{S}_{\mathrm{t}}=\alpha \mathrm{Y}_{\mathrm{t}} & 0<\alpha<1 \\ \mathrm{I}_{\mathrm{t}}=\beta\left[\mathrm{Y}_{\mathrm{t}}-\mathrm{Y}_{\mathrm{t}-1}\right] & \beta>0 \\ \mathrm{~S}_{\mathrm{t}}=\mathrm{I}_{\mathrm{t}} & \end{array}\)
where S t = Savings, Y t = Income, l t = Investment, t = time
In this model for economic growth, the condition for economic growth is