If the mean, mode and quartile deviation of a distribution is 2, 7 and 3, respectively, then Karl Pearson's coefficient of skewness is given by:
-10/9
Karl Pearson's coefficient of skewness is a common measure used to understand the asymmetry of a probability distribution. It indicates whether the data is skewed to the left (negatively skewed) or to the right (positively skewed), or if it is symmetrical.
There are two main formulas for Karl Pearson's coefficient of skewness:
In this question, we are given the mean, mode, and quartile deviation. This suggests we should use the first formula involving the mean and mode. However, the formula requires the standard deviation (SD), which is not directly provided. We are given the quartile deviation (QD).
For many distributions, especially those that are roughly symmetrical or unimodal, there's an approximate relationship between the Quartile Deviation and the Standard Deviation. A common approximation, particularly related to the normal distribution, is:
\(QD \approx \frac{2}{3} \times SD\)
From this, we can estimate the Standard Deviation:
\(SD \approx \frac{3}{2} \times QD\)
Given the quartile deviation (QD) is 3, we can estimate the standard deviation:
\(SD \approx \frac{3}{2} \times 3 = \frac{9}{2} = 4.5\)
Now we have the necessary components to calculate Karl Pearson's coefficient of skewness using the formula \(Sk = \frac{\text{Mean} - \text{Mode}}{SD}\).
Given values:
Estimated Standard Deviation (SD) = 4.5
Let's plug the values into the formula:
\(Sk = \frac{\text{Mean} - \text{Mode}}{SD}\)
\(Sk = \frac{2 - 7}{4.5}\)
\(Sk = \frac{-5}{4.5}\)
To simplify the fraction, we can write 4.5 as \(\frac{9}{2}\):
\(Sk = \frac{-5}{9/2}\)
\(Sk = -5 \times \frac{2}{9}\)
\(Sk = \frac{-10}{9}\)
The calculated Karl Pearson's coefficient of skewness is \(-10/9\).
| Step | Description | Calculation |
|---|---|---|
| 1 | Identify Given Values | Mean=2, Mode=7, QD=3 |
| 2 | Estimate SD using QD | \(SD \approx \frac{3}{2} \times QD = \frac{3}{2} \times 3 = 4.5\) |
| 3 | Calculate Skewness | \(Sk = \frac{\text{Mean} - \text{Mode}}{SD} = \frac{2 - 7}{4.5}\) |
| 4 | Simplify Result | \(Sk = \frac{-5}{4.5} = \frac{-5}{9/2} = -5 \times \frac{2}{9} = \frac{-10}{9}\) |
This result, \(-10/9\), matches one of the provided options. The negative value indicates that the distribution is negatively skewed, meaning it has a longer tail on the left side.
| Measure | Description | How it Describes Distribution |
|---|---|---|
| Mean | Average value | Center of mass |
| Median | Middle value | Center of position (50th percentile) |
| Mode | Most frequent value | Peak of the distribution |
| Standard Deviation | Spread of data points around the mean | Variability or dispersion |
| Quartile Deviation | Half of the Interquartile Range (IQR) | Spread of the middle 50% of data |
| Skewness | Asymmetry of the distribution | Shape (left-skewed, right-skewed, symmetrical) |
Karl Pearson's coefficient of skewness helps us understand the shape of the distribution in terms of its symmetry. Here's a simple interpretation:
It's important to remember that the relationship \(SD \approx \frac{3}{2} \times QD\) is an approximation often used in contexts like the normal distribution. Using this approximation is necessary here because the standard deviation is not directly given, but the quartile deviation is, alongside the mean and mode required for Karl Pearson's first formula.
Which of the following is a merit of data tabulation?
In seasonal variations, the duration of time is not more than:
If a constant is added to each observation of a data set, then which of the following measures of dispersion will change?
Which of the following is NOT true for seasonal variation?
The analysis of variance technique was developed by:
For the series 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, the minimum possible value of \(\rm \Sigma_{i=1}^n(x_i-A)^2\) can be attained at:
Suppose that a sample of 100 independent draws from a normal distribution having unknown mean μ and known variance σ2 = 1 is observed. If the sample mean is 5, then the 95% confidence interval for μ is:
Consider the following ANOVA table.
| Source of variation | Degrees of freedom | The sum of Squares (SS) | Mean SS | F Ratio |
| Treatments | a | b | c | 5 |
| Error | 12 | d | 20 | |
| Total | 15 | 540 |
The component containing the overall upward or downward pattern of the data in an annual time series is:
If the 25th, 50th and 75th percentile of a frequency distribution are equal to 2, 3 and 4, respectively, then the distribution is:
Match the following:
| (a) Marginalist Revolution | (i) Samuelson |
| (b) Multiplier-Accelerator model | (ii) J. R. Hicks |
| (c) IS-LM curves | (iii) Jevous |
| (d) Real Business Cycle | (iv) Robert J. Borro |
Choose the correct option from those given below:
As per the SRS Bulletin of September 2017, the estimated death rate for Kerala is 7.6, while for Bihar it is 6. From these data which is the correct inference to draw?
Arrange the following States in descending order according to Maternal Mortality Ratio (MMR) as per the Special Bulletin of SRS, May, 2018:
(i) Assam
(ii) Bihar
(iii) Madhya Pradesh
(iv) Uttar Pradesh
Choose the correct answer from the code given below :
Which of the following statements is true for the Indian economy according to the World Bank figures for 2017?
Harrod's Growth model is given as under:
\(\begin{array}{ll} \mathrm{S}_{\mathrm{t}}=\alpha \mathrm{Y}_{\mathrm{t}} & 0<\alpha<1 \\ \mathrm{I}_{\mathrm{t}}=\beta\left[\mathrm{Y}_{\mathrm{t}}-\mathrm{Y}_{\mathrm{t}-1}\right] & \beta>0 \\ \mathrm{~S}_{\mathrm{t}}=\mathrm{I}_{\mathrm{t}} & \end{array}\)
where S t = Savings, Y t = Income, l t = Investment, t = time
In this model for economic growth, the condition for economic growth is