Which one of the following equations does not have real roots ?
4x 2 + 9x + 6 = 0
A quadratic equation has the general form \( ax^2 + bx + c = 0 \), where \( a \), \( b \), and \( c \) are constants and \( a \neq 0 \). The nature of the roots (solutions) of a quadratic equation depends on the value of the discriminant, which is denoted by the Greek letter delta (\( \Delta \)) and calculated using the formula:
\( \Delta = b^2 - 4ac \)
Based on the value of the discriminant, we can determine if the quadratic equation has real roots:
To find which of the given quadratic equations does not have real roots, we need to calculate the discriminant \( \Delta \) for each equation and check if \( \Delta < 0 \).
In this equation, the coefficients are \( a = 2 \), \( b = 16 \), and \( c = 3 \).
Let's calculate the discriminant:
\( \Delta = b^2 - 4ac \)
\( \Delta = (16)^2 - 4(2)(3) \)
\( \Delta = 256 - 24 \)
\( \Delta = 232 \)
Since \( \Delta = 232 > 0 \), this equation has two distinct real roots.
In this equation, the coefficients are \( a = 2 \), \( b = 10 \), and \( c = -1 \).
Let's calculate the discriminant:
\( \Delta = b^2 - 4ac \)
\( \Delta = (10)^2 - 4(2)(-1) \)
\( \Delta = 100 + 8 \)
\( \Delta = 108 \)
Since \( \Delta = 108 > 0 \), this equation has two distinct real roots.
In this equation, the coefficients are \( a = 1 \), \( b = -8 \), and \( c = 1 \).
Let's calculate the discriminant:
\( \Delta = b^2 - 4ac \)
\( \Delta = (-8)^2 - 4(1)(1) \)
\( \Delta = 64 - 4 \)
\( \Delta = 60 \)
Since \( \Delta = 60 > 0 \), this equation has two distinct real roots.
In this equation, the coefficients are \( a = 4 \), \( b = 9 \), and \( c = 6 \).
Let's calculate the discriminant:
\( \Delta = b^2 - 4ac \)
\( \Delta = (9)^2 - 4(4)(6) \)
\( \Delta = 81 - 96 \)
\( \Delta = -15 \)
Since \( \Delta = -15 < 0 \), this equation has no real roots.
Based on the discriminant values calculated for each quadratic equation, the equation \( 4x^2 + 9x + 6 = 0 \) is the only one with a negative discriminant (\( \Delta = -15 \)). Therefore, this equation does not have real roots; it has complex roots.
| Equation | a | b | c | Discriminant \( \Delta = b^2 - 4ac \) | Nature of Roots |
|---|---|---|---|---|---|
| \( 2x^2 + 16x + 3 = 0 \) | 2 | 16 | 3 | \( 16^2 - 4(2)(3) = 256 - 24 = 232 \) | Real and Distinct (\( \Delta > 0 \)) |
| \( 2x^2 + 10x - 1 = 0 \) | 2 | 10 | -1 | \( 10^2 - 4(2)(-1) = 100 + 8 = 108 \) | Real and Distinct (\( \Delta > 0 \)) |
| \( x^2 - 8x + 1 = 0 \) | 1 | -8 | 1 | \( (-8)^2 - 4(1)(1) = 64 - 4 = 60 \) | Real and Distinct (\( \Delta > 0 \)) |
| \( 4x^2 + 9x + 6 = 0 \) | 4 | 9 | 6 | \( 9^2 - 4(4)(6) = 81 - 96 = -15 \) | No Real Roots (\( \Delta < 0 \)) |
This table summarizes how the discriminant determines the nature of roots for a quadratic equation \( ax^2 + bx + c = 0 \).
| Discriminant \( \Delta \) | Nature of Roots |
|---|---|
| \( \Delta > 0 \) | Two distinct real roots |
| \( \Delta = 0 \) | One real root (repeated) |
| \( \Delta < 0 \) | No real roots (Two complex conjugate roots) |
When a quadratic equation has no real roots (i.e., \( \Delta < 0 \)), its roots are complex numbers. These complex roots always appear as a conjugate pair. The quadratic formula provides the roots:
\( x = \frac{-b \pm \sqrt{\Delta}}{2a} \)
If \( \Delta < 0 \), we can write \( \sqrt{\Delta} = \sqrt{-1 \cdot |\Delta|} = \sqrt{-1} \cdot \sqrt{|\Delta|} = i \sqrt{|\Delta|} \), where \( i \) is the imaginary unit (\( i^2 = -1 \)). The roots then become:
\( x = \frac{-b \pm i \sqrt{|\Delta|}}{2a} \)
These are the complex conjugate roots, having the form \( p \pm qi \), where \( p = \frac{-b}{2a} \) and \( q = \frac{\sqrt{|\Delta|}}{2a} \).
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Question :
Does the equation ax 2+ bx + c = 0 have real roots of opposite sign?
Statement – I : The discriminant D > 0
Statement – II : c / a > 0
Which one of the following is correct in respect of the question and the statements?
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