If the roots of the equation x2 - bx + c = 5 differ by 5, then which one of the following is correct ?
b2 = 4c + 5
The problem asks us to find a relationship between the coefficients b and c of a quadratic equation, given a specific condition about its roots. The equation provided is \(x^2 - bx + c = 5\). A key piece of information is that the roots of this equation differ by 5.
First, let's rewrite the given equation in the standard quadratic form, which is \(ax^2 + Bx + C = 0\). Subtracting 5 from both sides gives us:
\(x^2 - bx + (c - 5) = 0\)
In this standard form, we have \(a = 1\), \(B = -b\), and \(C = (c - 5)\).
Vieta's formulas relate the coefficients of a polynomial to the sums and products of its roots. For a quadratic equation \(ax^2 + Bx + C = 0\), let the roots be \(\alpha\) and \(\beta\). The formulas are:
Applying these to our equation \(x^2 - bx + (c - 5) = 0\):
The question states that the roots differ by 5. We can express this condition mathematically as:
\(|\alpha - \beta| = 5\)
Squaring both sides, we get:
\((\alpha - \beta)^2 = 5^2 = 25\)
There is a useful identity that connects the square of the difference of roots to the sum and product of the roots:
\((\alpha - \beta)^2 = (\alpha + \beta)^2 - 4\alpha\beta\)
Now, we can substitute the expressions for the sum and product of roots that we found using Vieta's formulas:
Substituting these into the identity:
\(25 = (b)^2 - 4(c - 5)\)
Let's simplify the equation:
\(25 = b^2 - 4(c - 5)\)
Distribute the -4:
\(25 = b^2 - 4c + 20\)
Now, we want to isolate \(b^2\) to match the format of the options. Subtract 20 from both sides:
\(25 - 20 = b^2 - 4c\)
\(5 = b^2 - 4c\)
Finally, add \(4c\) to both sides to get the desired form:
\(b^2 = 4c + 5\)
The relationship derived, \(b^2 = 4c + 5\), matches one of the provided options. This equation holds true if the roots of the quadratic equation \(x^2 - bx + c = 5\) differ by 5.
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