All Exams Test series for 1 year @ ₹349 only
Question

Which of the following statement(s) is/are TRUE?

I. √64 + √(0.0064) + √(0.81) + √(0.0081) = 9.07

II. √(0.010201) + √(98.01) + √(0.25) = 11.51

This question was previously asked in
SSC CGL 2017 (Tier 1) Previous Year Paper (16-Aug-2017) (Shift 1)
The correct answer is

Only I

Statement I:

\(\sqrt{64}+\sqrt{0.0064}+\sqrt{0.81}+\sqrt{0.0081} = 8+0.08+0.9+0.09 = 9.07\)TRUE.

Statement II:

\(\sqrt{0.010201}+\sqrt{98.01}+\sqrt{0.25} = 0.101+9.9+0.5 = 10.501 \neq 11.51\)FALSE.

Hence only I is true.

Was this answer helpful?

Similar Questions

  1. The value of 51 ÷ (25 + {25 of 12 ÷ 30) - (54 ÷ 5 of 125)} is:

  2. If p = \(\frac{\sqrt{2}+1}{\sqrt{2}-1}\) and q = \(\frac{\sqrt{2}-1}{\sqrt{2}+1}\) then find the value of \(\frac{p^2}{q}+\frac{q^2}{p}\) .

  3. If b = 5, determine the value of an expression \(({5 \over b} + 5b)\)\(({25 \over b^2} - 25 + 25b^2)\) using an identity.

  4. Sinplify: \(\sqrt {36{x^2} - 108x + 81} \).

  5. Find the value of the given expression.

    \(\sqrt{20 - \sqrt{20 - \sqrt{20 - \sqrt{20 - \ ...\infty}}}}\)

  6. If x = \(\sqrt{64}+ \sqrt{121} - \sqrt{169}\), then find the value of x2.

  7. The value of (0.3) [{(200 - 146)/(3 × 3 × 3)} - 3] is:

  8. If x 2a = y 2b = z 2c ≠ 0 and x 2= yz, then the value of \(\frac{{ab + bc + ca}}{{bc}}\) is:

  9. Simplify the following expression.

    \(\frac{7.35\times7.35-2.25\times2.25}{0.24}\)

  10. What is the value of \(\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}−\sqrt{5}} \div \frac{\sqrt{14}+\sqrt{10}}{\sqrt{14}−\sqrt{10}}+\frac{\sqrt{10}}{\sqrt{5}}\) ?


Important Questions from Surds and Indices

  1. The value of \(\frac{{{{\left( {251} \right)}^3} + {{\left( {249} \right)}^3}}}{{25.1 \times 25.1 - 624.99 + 24.9 \times 24.9}}\)  is 5 × 10 , where the value of k is :

  2. Find the value of m in \(\left(\frac{2}{7}\right)^{-3} \times \left(\frac{2}{7}\right)^{-5}=\left (\frac{2}{7}\right)^{-3m+1}\)

  3. If √625 = 25; then√(.00000625/25)is:

    A. 0.0025

    B. 0.001

    C. 0.0001

    D. 0.0005
  4. Find the value of:

    \(\sqrt{150}-\sqrt{54}-\sqrt{24}\)

  5. If \(\sqrt{4624}=68\) , then the value of:

    \(\sqrt{46.24}+\sqrt{0.4624}+\sqrt{0.004624}\)

Need Expert Advice?
Upcoming Exams
SSC JHT
September 08, 2026
SSC Stenographer
September 09, 2026
SSC Selection Post
September 16, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2500 Tests 6 Tests Free
3990 Attempts
4.2(838)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App