$24^{-33}$
The question asks us to simplify the mathematical expression $24^{-10} \div 24^{16} \times 24^{-7}$. This involves using the rules of exponents, specifically for division and multiplication of powers with the same base.
To solve this, we need to remember two fundamental rules of exponents:
Let's apply these rules to the given expression $24^{-10} \div 24^{16} \times 24^{-7}$. We'll work from left to right.
First, we handle the division part: $24^{-10} \div 24^{16}$. Using the division rule ($a^m \div a^n = a^{m-n}$), we subtract the exponents:
$ 24^{-10} \div 24^{16} = 24^{-10 - 16} = 24^{-26} $Now, we take the result from Step 1 and multiply it by the next term: $24^{-26} \times 24^{-7}$. Using the multiplication rule ($a^m \times a^n = a^{m+n}$), we add the exponents:
$ 24^{-26} \times 24^{-7} = 24^{-26 + (-7)} = 24^{-26 - 7} = 24^{-33} $After applying the rules of exponents step-by-step, the simplified value of the expression $24^{-10} \div 24^{16} \times 24^{-7}$ is $24^{-33}$.
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