Given that $50^{0.92} = x$, $50^{0.26}= y$ and $x^z = y^3$, then the value of z is close to:
We are given a problem involving exponents and variables. We need to find the value of $z$ based on the relationships provided:
The goal is to use the properties of exponents to solve for $z$.
Follow these steps to find the value of $z$:
Now, perform the division to find the value of $z$:
$ z = \frac{0.78}{0.92} $To calculate this value:
$ z \approx 0.847826... $Rounding this value to two decimal places, we get $z$ $\approx$ 0.85.
Therefore, the value of $z$ is close to 0.85.
Find the value of $47^{-8} \div 47^3 \times 47^{-19}$.
Given that $58^{0.5} = x$, $58^{0.79}= y$ and $x^z = y^{10}$, then the value of z is close to:
The value of $8^{2} + \sqrt{ 3^{2} } -2 \sqrt{36} -11$ is