If M = 0.1 + (0.1) 2+ (0.01) 2and N = 0.3 + (0.03) 2+ (0.003) 2, then what is the value of M + N?
0.411009
Compute each term directly:
\(M = 0.1 + (0.1)^2 + (0.01)^2 = 0.1 + 0.01 + 0.0001 = 0.1101\)
\(N = 0.3 + (0.03)^2 + (0.003)^2 = 0.3 + 0.0009 + 0.000009 = 0.300909\)
Therefore M + N = 0.110100 + 0.300909 = 0.411009.
Similar Questions
The value of (0.3) [{(200 - 146)/(3 × 3 × 3)} - 3] is:
Simplify the following.
\(\frac{\sqrt{10+\sqrt{25+\sqrt{108+\sqrt{154+\sqrt{225}}}}}}{\sqrt{16+19.25\times4^2}}\)
If x = \(\sqrt{64}+ \sqrt{121} - \sqrt{169}\), then find the value of x2.
The expression \(\frac{{15\left( {\sqrt {10} + \sqrt 5 } \right)}}{{\sqrt {10\;} + \sqrt {20} + \sqrt {40} - \sqrt 5 - \sqrt {80} }}\) is equal to:
If \(x = \sqrt {-\sqrt 3 + \sqrt {3 + 8\sqrt {7 + 4\sqrt 3}}}\) where x > 0, then the value of x is equal to:
What is the value of \(\frac{\sqrt{7}+\sqrt{5}}{\sqrt{7}−\sqrt{5}} \div \frac{\sqrt{14}+\sqrt{10}}{\sqrt{14}−\sqrt{10}}+\frac{\sqrt{10}}{\sqrt{5}}\) ?
One of the factors of (8 2k + 5 2k ), where k is an odd number, is:
What is the value of \(\sqrt {4600 + \sqrt {540 + \sqrt {1280 + \sqrt {250 + \sqrt {36} } } } } \;?\)
What is the value of √121 + √12321 + √1234321 + √123454321?
Which of the following statement(s) is/are TRUE?
I. 33 3> 3 33
II. 333 > (3 3) 3
Important Questions from Surds and Indices
Find the cube root of 78402752
Find the value of :
[(3 × 3 × 3 × 3 × 3 × 3) 6 ÷ (3 × 3 × 3 × 3) 7 × 3 4]
The cube root of - 64 × - 1331 is:
If (27) m = (81) n, then m 2: mn = ?
if 49 n + 49 n + 49 n + 49 n + 49 n + 49 n + 49 n = 7 2221 , then n = ?
