Which of the following statement is correct? I. If x = 12, y = -2 and z = -10, then x3 + y3 + z3 = 360. II. If x + y = 48 and 4xy = 128, then 4x2 + 4y2 = 4480.
Neither I nor II
We are asked to evaluate two algebraic statements and determine which one is correct. Let's analyze each statement individually.
Statement I gives us the values \(x = 12\), \(y = -2\), and \(z = -10\). We need to check if \(x^3 + y^3 + z^3\) equals 360.
First, let's calculate the sum \(x+y+z\):
\(x+y+z = 12 + (-2) + (-10)\)
\(x+y+z = 12 - 2 - 10\)
\(x+y+z = 10 - 10\)
\(x+y+z = 0\)
There is a useful algebraic identity that states: If \(x+y+z=0\), then \(x^3+y^3+z^3 = 3xyz\).
Since we found that \(x+y+z = 0\), we can use this identity to calculate \(x^3+y^3+z^3\):
\(x^3+y^3+z^3 = 3xyz\)
\(x^3+y^3+z^3 = 3 \times (12) \times (-2) \times (-10)\)
\(x^3+y^3+z^3 = 36 \times (20)\)
\(x^3+y^3+z^3 = 720\)
The statement claims that \(x^3 + y^3 + z^3 = 360\). Our calculation shows that \(x^3 + y^3 + z^3 = 720\). Since \(720 \neq 360\), Statement I is incorrect.
Statement II gives us two conditions: \(x+y = 48\) and \(4xy = 128\). We need to check if \(4x^2 + 4y^2\) equals 4480.
From the second condition, \(4xy = 128\), we can find the value of \(xy\):
\(xy = \frac{128}{4}\)
\(xy = 32\)
We need to evaluate \(4x^2 + 4y^2\), which can be factored as \(4(x^2 + y^2)\).
We know the algebraic identity for the square of a sum: \((x+y)^2 = x^2 + 2xy + y^2\).
We can rearrange this identity to find \(x^2 + y^2\):
\(x^2 + y^2 = (x+y)^2 - 2xy\)
Now, substitute the given values \(x+y = 48\) and \(xy = 32\) into this expression:
\(x^2 + y^2 = (48)^2 - 2(32)\)
Calculate \(48^2\):
\(48^2 = 48 \times 48 = 2304\)
Calculate \(2 \times 32\):
\(2 \times 32 = 64\)
Now, substitute these values back into the expression for \(x^2 + y^2\):
\(x^2 + y^2 = 2304 - 64\)
\(x^2 + y^2 = 2240\)
Finally, calculate \(4x^2 + 4y^2 = 4(x^2 + y^2)\):
\(4(x^2 + y^2) = 4(2240)\)
\(4(2240) = 8960\)
The statement claims that \(4x^2 + 4y^2 = 4480\). Our calculation shows that \(4x^2 + 4y^2 = 8960\). Since \(8960 \neq 4480\), Statement II is incorrect.
Based on our analysis, both Statement I and Statement II are incorrect.
| Statement | Given/Conditions | Claim | Calculated Value | Correctness |
|---|---|---|---|---|
| I | \(x=12, y=-2, z=-10\) | \(x^3 + y^3 + z^3 = 360\) | \(x^3 + y^3 + z^3 = 720\) | Incorrect |
| II | \(x+y=48, 4xy=128\) | \(4x^2 + 4y^2 = 4480\) | \(4x^2 + 4y^2 = 8960\) | Incorrect |
Therefore, neither Statement I nor Statement II is correct.
Understanding basic algebraic identities is crucial for solving problems like this. Here are some relevant identities:
When asked to verify algebraic statements, it's important to follow a systematic approach:
In Statement I, recognising the condition \(x+y+z=0\) is key to using the simpler identity \(x^3+y^3+z^3 = 3xyz\). Calculating \(x^3\), \(y^3\), and \(z^3\) separately and summing them up would also work but might be more calculation-intensive for larger numbers.
In Statement II, using the identity \((x+y)^2 = x^2 + 2xy + y^2\) to find \(x^2+y^2\) is a standard technique when \(x+y\) and \(xy\) are known. This avoids needing to find the individual values of \(x\) and \(y\) first (which would involve solving a quadratic equation).
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